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ipn [44]
3 years ago
15

Analyze the graph of the cube root function shown on the right to determine the transformations of the parent function. Then, de

termine the values of a, h, and k in the general equation. y = a RootIndex 3 StartRoot x minus h EndRoot + k h = k = On a coordinate plane, a cubic function approaches the x-axis in quadrant 2, crosses the y-axis at (0, 2), has an inflection point at (1, 4), and the goes through (2, 6).
Mathematics
2 answers:
ollegr [7]3 years ago
4 0

Answer:

h=1

k=4

a=2

Step-by-step explanation:

its one edge

Schach [20]3 years ago
3 0

Answer:

B

Step-by-step explanation:

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Find the range of the product. <br> 34 x 47
stepladder [879]
34 x 47 = 1598 so that’s the range
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Pls help this is my final decimal review homework then. I move on to other math if I run out of points to post I will try and ge
goblinko [34]

Answer:

1. 3.050

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6 0
3 years ago
Max spends $5.25 on gas for his lawn mower. He earns $12.00 mowing his neighbor's yard. What is Max's profit?
Mila [183]

Answer:

$6.75 aint never seen to pretty best frineds and always one of em' gotta be ugly

Step-by-step explanation:

5 0
3 years ago
A right triangle has one angle that measure 23o. The adjacent leg measures 27.6 cm and the hypotenuse measures 30 cm. What is th
Mnenie [13.5K]
First, we need to find the opposite side.
opposite^2 = 30^2 -27.6^2
opposite^2 = 900 -761.76
opposite^2 = 138.24
opposite side = <span> <span> <span> 11.7575507654 </span> </span> </span>

Right Triangle Area = (adj * opp) / 2
Right Triangle Area = (27.6 * 11.758) / 2
Right Triangle Area = 324.51 / 2
Right Triangle Area = 162.25

Answer is 161.7 cm^2





4 0
2 years ago
Show that if a and b are positive integers, then ab = gcd (a, b). lcm (a, b) . [Hint: Use prime factorizations of a and b and th
AleksandrR [38]

Answer:

ab=\gcd(a,b)\cdot \text{lcm}(a,b)

Step-by-step explanation:

Using the hint, write a and b in the following prime factorization:

a=p_1^{x_1}p_2^{x_2}\cdots p_t^{x_t}\cdot q,

b=p_1^{y_1}p_2^{y_2}\cdots p_t^{y_t}\cdot r,

where  \gcd(p_i,r)=1,\ \gcd(p_i,q)=1,\ \gcd(r,q)=1,\ \gcd(p_i,p_j)=1, for i ≠ j.

Then by the formulae for gcd(a,b) and lcm(a,b) we know that:

\gcd(a,b)=p_1^{\min(x_1,y_1)}p_2^{\min (x_2,y_2)} \cdots p_t^{\min(x_t,y_t)}

\text{lcm}(a,b)= q\cdot r\cdot p_1^{\max(x_1,y_1)}p_2^{\max(x_2,y_2)}\cdots p_t^{\max(x_t,y_t)}

Note that the expression \min(x_i,y_i)+\max(x_i,y_i)=x_i+y_i for all i, since if the minimum is, <em>without loss of generality</em>, x_i, then the maximum must be y_i, and viceversa. Then, it is straightforward to verify that when we multiply gcd(a, b) and lcm(a, b) its prime factorization matches the prime factorization of ab, and so we can see the equaility holds:

\gcd(a,b)\cdot \text{lcm}(a,b)=ab.

7 0
3 years ago
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