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poizon [28]
4 years ago
15

How does changing the direction of moving wire in a magnetic field affect the current

Physics
1 answer:
Tanya [424]4 years ago
4 0

Moving a wire in a magnetic field produces a voltage between the ends of the wire (and a current in the wire if there's any conductor between the ends of the wire).

If the direction of the motion is exactly reversed, then the voltage (and the current) become negative but with the same size.

By changing the direction of the motion, the size of the voltage (and current) can be changed to anything between zero and the maximum.  It's zero when the wire moves parallel to the magnetic field, and maximum when the wire moves perpendicular to the magnetic field.

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When light travels through a small hole, it appears to an observer that the light spreads out, blurring the outline of the hole.
Scilla [17]

wave theory

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The doctor writes a prescription for na heparin 20,000 units in 500 ml n.s. infuse over 8 hours. what is the flow rate in ml/hr?
Ne4ueva [31]
I think this type of equation could be conducted in simple division equation since it does not involve drop rate.

we know that there is 500 ml of substance and should be infused within 8 hours period.

So the flow rate in ml/hr would be: 

500/8 = 62.5 ml/hr                                                                                    
8 0
3 years ago
A current-carrying wire oriented north-south and laid over a compass deflects the compass 8° to the east. What is the magnitude
zhenek [66]

2.8 \times 10^{-6}\ T is the magnitude of the magnetic field made by the current

<u>Explanation:</u>

Given data:

\theta=8^{\circ}

Magnetic field of earth, B_{\text {earth}}=2 \times 10^{-5}\ \text {tesla}

We need to find the magnetic field of wire, B_{\text {wire }}

The compass needle moves toward a direction of magnetic field. The current in wire makes a magnetic field in available space where the compass is on the ground. The vector sum of the Earth's magnetic field and the wire's magnetic field represents the net magnetic field, as shown in the attached drawing, expressing the angle:

                   \tan \theta=\frac{B_{\text {wire}}}{B_{\text {earth}}}

By substituting the given values, we get

                  B_{\text {wire}}=\tan \theta \times B_{\text {earth}}=\tan 8^{\circ} \times 2 \times 10^{-5}=0.1405 \times 2 \times 10^{-5}

                  B_{\text {wire}}=0.28 \times 10^{-5}=2.8 \times 10^{-6}\ T

4 0
3 years ago
Which TWO correctly relate the attraction between the particles of a liquid and the temperature at which the liquid changes stat
Naddika [18.5K]
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7 0
3 years ago
Read 2 more answers
Light from a laser (lambda= 406.192 nm) is used to illuminate two narrow slits. The interference pattern is observed on a screen
dsp73

Answer:

The spacing between the slits is    d = 0.00145m                

Explanation:

From the question we are told that

  The wavelength of the light is \lambda = 406.192nm = 406.192*10^{-9} m

   The distance of the slit from the screen is D = 5.937 \ m

    The number of bright fringe is n = 24

     The  length the fringes span is   L = 39.835 mm = \frac{39.835 }{1000} = 0.0398 m

The fringe width (i.e the distance of between two successive bright or dark fringe) is mathematically represented as

             \beta  = \frac{\lambda D}{d}

Where d is  the distance between the  slits

            \beta is the fringe width which can also be evaluated as

                         \beta = \frac{L}{n}

Substituting values

                        \beta = \frac{0.0398}{24}

                          \beta = 1.660 *10^{-3}

Making d the subject of formula in the above equation

                d = \frac{\lambda D}{\beta }

Substituting values

                d = \frac{406.192 *10^{-9} * 5.937 }{1.660 *10^{-3}}

                    d = 0.00145m                

           

4 0
4 years ago
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