The correct answer is Democritus
Explanation:
a) The height of the ball h with respect to the reference line is

so its initial gravitational potential energy
is



b) To find the speed of the ball at the reference point, let's use the conservation law of energy:

We know that the initial kinetic energy
as well as its final gravitational potential energy
are zero so we can write the conservation law as

Note that the mass gets cancelled out and then we solve for the velocity v as



Answer:
a
Explanation:hope this helps
Answer:
(A) Fo = 72 Hz
(B) The pipe is open at both ends
(C) The length of the pipe is 2.38m
This problem involves the application of the knowledge of standing waves in pipes.
Explanation:
The full solution can be found in the attachment below.
For pipes open at both ends the frequency of the pipe is given by
F = nFo = nv/2L where n = 1, 2, 3, 4.....
For pipes closed at one end the frequency of the pipe is given by
F = nFo = nv/4L where n = 1, 3, 5, 7...
The full solution can be found in the attachment below.
Answer:
x2 = 0.99
Explanation:
from superheated water table
at pressure p1 = 0.6MPa and
temperature 200 degree celcius
h1 = 2850.6 kJ/kg
From energy equation we have following relation


![(h1 + \frac{v1^2}{2} = (h2 + \frac{v2^2}{2}[tex]2850.6 + \frac{50^2}{2} *\frac{1 kJ/kg}{1000 m^2/s^2} = h2 + \frac{600^2}{2} *\frac{1 kJ/kg}{1000 m^2/s^2}](https://tex.z-dn.net/?f=%28h1%20%2B%20%5Cfrac%7Bv1%5E2%7D%7B2%7D%20%3D%20%28h2%20%2B%20%5Cfrac%7Bv2%5E2%7D%7B2%7D%3C%2Fp%3E%3Cp%3E%3C%2Fp%3E%3Cp%3E%5Btex%5D2850.6%20%2B%20%5Cfrac%7B50%5E2%7D%7B2%7D%20%2A%5Cfrac%7B1%20kJ%2Fkg%7D%7B1000%20m%5E2%2Fs%5E2%7D%20%3D%20h2%20%2B%20%5Cfrac%7B600%5E2%7D%7B2%7D%20%2A%5Cfrac%7B1%20kJ%2Fkg%7D%7B1000%20m%5E2%2Fs%5E2%7D)
h2 = 2671.85 kJ/kg
from superheated water table
at pressure p2 = 0.15MPa
specific enthalpy of fluid hf = 467.13 kJ/kg
enthalpy change hfg = 2226.0 kJ/kg
specific enthalpy of the saturated gas hg = 2693.1 kJ/kg
as it can be seen from above value hf>h2>hg, so phase 2 is two phase region. so we have
quality of steam x2
h2 = hf + x2(hfg)
2671.85 = 467.13 +x2*2226.0
x2 = 0.99