Answer:
Heat of vaporization will be 22.59 j
Explanation:
We have given mass m = 10 gram
And heat of vaporization L = 2.259 J/gram
We have to find the heat required to vaporize 10 gram mass
We know that heat of vaporization is given by 
, here m is mass and L is latent heat of vaporization.
So heat of vaporization Q will be = 10×2.259 = 22.59 J
Answer:
A = 1.54 x 10⁻⁵ m² = 15.4 mm²
Explanation:
The resistance of a wire can be given by the following formula:
where,
A = smallest cross-sectional area = ?
ρ = resistivity of copper = 1.54 x 10⁻⁸ Ωm
= resistance per unit length of wire = 0.001 Ω/m
Therefore,
<u>A = 1.54 x 10⁻⁵ m² = 15.4 mm²</u>
Answer:
c. is negative
Explanation:
When the magnitude of force is multiplied with the force vector's projection along the direction of the vector of displacement which is negative as it is a resistive force we get the work done.
As the wind is acting in opposite direction of the force which is being applied by the plane the work done will be negative. Also, the net work will be the sum of many smaller negative quantities.
Hence, the answer here is negative.
Answer:
a) Δx = 180.59 m
b) T = 6001 N
Explanation:
a)
According to Newton's second law, which says that acceleration is directly proportional to the net force, the equation is equal to:
ΣF = m*a = T-f
Clearing a, and solving:
a = (T-f)/m = (T-f)/2*m = (12000-5800)/(2*700) = 4.43 m/s^2
To evaluate the final speed the following equation will be used:
vf^2 = vi^2 + 2*a*Δx = 0 + 2*a*Δx = 2*a*Δx
Clearing Δx:
Δx = vf^2/2*a = (40 m/s)^2/(2* 4.43 m/s^2) = 180.59 m
b)
The tension is equal to:
T = m*a + f = (700 kg * 4.43 m/s^2) + 2900 N = 6001 N
A hammer is a type of lever.
