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Serjik [45]
3 years ago
10

When you measure something in meters cubed, you are measuring ____.

Physics
2 answers:
Shalnov [3]3 years ago
7 0
I think your answer is volume

raketka [301]3 years ago
3 0
Volume, hope it helps!
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Một oto đang chạy với vận tốc là 10m/s thì tăng tốc và chuyển động nhanh dần đều sau 20s thì đạt vận tốc 14m/s
Tasya [4]

a) gia tốc = vf-vi / t

a = 14-10 / 20

a = 0,2ms⁻²

b) dưới dạng a = Δv / t

v = lúc

v = 0,2 × 40

v = 8ms⁻¹

như v = d / t

do đó d = vt

d = 8 × 40

d = 320m

hãy đánh dấu là trí óc nhất

4 0
3 years ago
Bonus Points. A ball was thrown straight up in the air from 1.2 meter above the grouind. After 3 seconds the ball returnes to th
nekit [7.7K]

Answer:

Explanation:

given that

Distance above the ground, s = 1.2 m

Time taken by the ball, t = 3 s

Velocity of the ball, v = 1.2/3 = 0.4 m/s

Maximum height reached by the ball is then given by the formula

H = v² / 2g

H = 0.4² / 2 * 9.8

H = 0.16 / 19.6

H = 0.0082 m or rather, 0.82 cm

5 0
3 years ago
Why does rhododendron not grow well in the terai region of nepal give reason
Andrews [41]

Answer:

Tge Rhododendrob is the national flower of Nepal. The hills and mountain sides ranges of Nepal are decorated with diff colours and shapes

3 0
3 years ago
. (Serway 9th ed., 7-33) A 0.600-kg particle has a speed of 2.00 m/s at point A and a kinetic energy of 7.50 J at point B. What
k0ka [10]

Answer:

a) KA = 1.2 J

b) vB = 5.00 m/s

c) W = 6.30 J

Explanation:

m = 0.600 kg

vA = 2.00 m/s

KB = 7.50 J

a) KA = ?

b) vB = ?

c) W = ?

We can apply the folowing equations

K = 0.5*m*v²

and

W = ΔK = KB- KA

then

a) KA = 0.5*m*vA² = 0.5*(0.600 kg)*(2.00 m/s)²

⇒  KA = 1.2 J

b) KB = 0.5*m*vB²     ⇒     vB = √(2*KB / m)

⇒     vB = √(2*7.50 J / 0.600 kg)

⇒     vB = 5.00 m/s

c) W = ΔK = KB- KA = (7.50 J) - (1.2 J)

⇒     W = 6.30 J

5 0
4 years ago
A 5.0-kg block of wood is placed on a 2.0-kg aluminum frying pan. How much heat is required to raise the temperature of both the
Shalnov [3]

Heat required to raise the temperature of a given system is

Q = ms\Delta T

here we know that

m = mass

s = specific heat capacity

\Delta T = change in temperature

now as we know that

mass of wood = 5 kg

mass of aluminium pan = 2 kg

change in temperature = 45 - 20 = 25 degree C

specific heat capacity of wood = 1700 J/kg C

specific heat capacity of aluminium = 900 J/kg C

now here we will find the total heat to raise the temperature of both

Q = m_1s_1\Delta T_1 + m_2s_2\Delta T_2

Q = 5 * 1700 * 25 + 2 * 900 * 25

Q = 212500 + 45000

Q = 257500 J

So heat required to raise the temperature of the system is 257500 J

4 0
3 years ago
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