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4 years ago

If you use the same force on a less massive object what happens to the acceleration

1 answer:

5 0

Acceleration = Force/Mass

If F= 20N , M = 10KG , then A will be 2m/s^2

Now, if we use Same 20N force on 5kg mass, ,Then A will be 4m/s^2.
Therefore Acceleration will increase if u use same for on less massive objects

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Prove that the period of a simple pendulum T=2×22/7×rootl/g

Rudik [331]

Answer:

Explanation:

Check the attachment.

By the definition of the simple harmonic motion,

The motion of a particle whose acceleration is

1. Always directed towards the center of the motion.

2. Proportional to the distance from center of the motion.

We get, a ∝ -x

where

a = acceleration

x = distance of the particle from center of the motion

- sign says acceleration is in opposite direction of motion

Check the other attachment for proof of a = -ω²x (or a = -ω²y)

x and y are both use to denote distance from center of the motion

Download pdf

4 0

3 years ago

Which of the following activities could lead to injuries?

Ipatiy [6.2K]

Answer:

Fighting

Explanation:

Fighting with someone like punch for punch can make the person bleed which an injury to the guy who you fought with and you can be arrested if the parents file a complain at the police station

6 0

3 years ago

Read 2 more answers

Consider a ship of mass 2 x 10^6 kg with propeller blades of radius 7 m and it can push water backwards to a speed of 2 m/s. Giv

PolarNik [594]

Answer:

$a = 0.308 m/s^2$

Explanation:

As we know that the force due to propeller when it will push the water backwards is given as

$F = \frac{dP}{dt}$

now we know that

$P = mv$

so we have

$F = v\frac{dm}{dt}$

$F = v \rhoA\frac{dx}{dt}$

$F = \rho A v^2$

here we know that

$A = \pi r^2$

$A = \pi(7^2)$

$A = 154 m^2$

now the force is given as

$F = (1000)(154)(2^2)$

$F = 616000 N$

now the acceleration of the ship is given by Newton's II law

$a = \frac{F}{m}$

$a = \frac{616000}{2 \times 10^6}$

$a = 0.308 m/s^2$

3 0

3 years ago

In a Young's double-slit experiment, light of wavelength 500 nm illuminates two slits which are separated by 1 mm. The separatio

asambeis [7]

Answer:

Δx = 2.5 x 10⁻³ m = 2.5 mm

Explanation:

The distance between two consecutive fringes, also known as fringe spacing, in Young's Double Slit Experiment, is given as follows:

Δx = λL/d

where,

Δx = distance between consecutive fringes = ?

λ = wavelength of light = 500 nm = 5 x 10⁻⁷ m

L = Distance between slits and screen = 5 m

d = slit separation = 1 mm = 1 x 10⁻³ m

Therefore,

Δx = (5 x 10⁻⁷ m)(5 m)/(1 x 10⁻³ m)

4 0

3 years ago

A 600-N box is pushed up a ramp that is 2 meters high and 5 meters long. The person exerts a force of 300-N. What is the efficie

AfilCa [17]

From information given, there are two forces in action, the vertical and the horizontal. We first need to calculate separately work done by these two forces, then determine the efficiency. Work = Force × distance work(a) → 600N × 2m = 1,200 Nm work(b) → 300N × 5m = 1,500 Nm Efficiency = work(a) / work (b) × 100 Efficiency = 1200 / 1500 × 100 Efficiency = 0.8 × 100 Efficiency = 80% Therefore the efficiency of the ramp is 80%

6 0

3 years ago