Answer:
45200J
Explanation:
Given parameters:
Heat of vaporization of water = 2260J/g
Mass of steam = 20g
Temperature = 100°C
Unknown:
Energy released during the condensation = ?
Solution:
This change is a phase change and there is no change in temperature
To find the amount of heat released;
H = mL
m is the mass
L is the latent heat of vaporization
Insert the parameters and solve;
H = 20g x 2260J/g
H = 45200J
Use light-years as the unit of measurement <span />
A=pi r^2
A=( 3.14159.......)(12.77)^2
A= 512.30m^2
C) Staring At Someone's Body, Giving Them The “Once Over”
