Answer: its c In step 3, he should have divided both sides by StartFraction 6 Over 4 Endfraction.
Step-by-step explanation:
Answer:
<u>11 feet 2 inches</u>
Step-by-step explanation:
ill add the inches first
11+5+10= 26
26inches= 2ft 2inches
now I add the feet
2+3+4+2=11 feet
<u>11 feet 2 inches</u>
Answer:
y=39
Step-by-step explanation:
73-2y=-5
2y=73-(-5)
2y=73+5
2y=78
y=78/2
y=39
Answer: (2.54,6.86)
Step-by-step explanation:
Given : A random sample of 10 parking meters in a beach community showed the following incomes for a day.
We assume the incomes are normally distributed.
Mean income : 
Standard deviation : 


The confidence interval for the population mean (for sample size <30) is given by :-

Given significance level : 
Critical value : 
We assume that the population is normally distributed.
Now, the 95% confidence interval for the true mean will be :-

Hence, 95% confidence interval for the true mean= (2.54,6.86)