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swat32
3 years ago
10

Lily spent $73.94 on an e-reader. If the original price was $69.95, what

Mathematics
1 answer:
grandymaker [24]3 years ago
6 0

Answer:

5.70% or $3.99

Step-by-step explanation:

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Abigail and Mason are saving money to buy a CD that costs
maw [93]

Answer:

abigail

Step-by-step explanation:

abigail is correct because she has 30 dimes a dime is worth 30 cents and if 30 times ten equals 300 it would be 3 dollars so all together they have 6 dollars so now all they need is 3 dollars

I hope that made it easier for you good luck

6 0
3 years ago
What is the answer? Please answer correctly
Sloan [31]

Answer:

i think its 7t

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
What is 9-(-5) please help me​
elena-14-01-66 [18.8K]

9-(-5)=

9 + 5 (because - - = +)

14

thus 9-(-5) = 14

4 0
3 years ago
In ABC, what is the value of x<br><br> 5.5<br> 6.5<br> 55<br> 65
vekshin1

<em>Answer:</em>

( B ) x = 6.5

<em>Step-by-step explanation:</em>

We know that all the angles of a triangle equal 180 when added together. So lets make an equation for this question.

(10x-10) + (10x+8) + 8x = 180

I just took all the angles and added them together to make 180. Now solve for x.

10x - 10 + 10x + 8 + 8x = 180 <em>(combined like terms)</em>

28x -2 = 180 <em>(added 2 to both sides)</em>

28x = 182 <em>(divided both sides by 28)</em>

x = 6.5

6 0
3 years ago
Read 2 more answers
Litter such as leaves falls to the forest floor, where the action of insects and bacteria initiates the decay process. Let A be
Travka [436]

Answer:

D = L/k

Step-by-step explanation:

Since A represents the amount of litter present in grams per square meter as a function of time in years, the net rate of litter present is

dA/dt = in flow - out flow

Since litter falls at a constant rate of L  grams per square meter per year, in flow = L

Since litter decays at a constant proportional rate of k per year, the total amount of litter decay per square meter per year is A × k = Ak = out flow

So,

dA/dt = in flow - out flow

dA/dt = L - Ak

Separating the variables, we have

dA/(L - Ak) = dt

Integrating, we have

∫-kdA/-k(L - Ak) = ∫dt

1/k∫-kdA/(L - Ak) = ∫dt

1/k㏑(L - Ak) = t + C

㏑(L - Ak) = kt + kC

㏑(L - Ak) = kt + C'      (C' = kC)

taking exponents of both sides, we have

L - Ak = e^{kt + C'} \\L - Ak = e^{kt}e^{C'}\\L - Ak = C"e^{kt}      (C" = e^{C'} )\\Ak = L - C"e^{kt}\\A = \frac{L}{k}  - \frac{C"}{k} e^{kt}

When t = 0, A(0) = 0 (since the forest floor is initially clear)

A = \frac{L}{k}  - \frac{C"}{k} e^{kt}\\0 = \frac{L}{k}  - \frac{C"}{k} e^{k0}\\0 = \frac{L}{k}  - \frac{C"}{k} e^{0}\\\frac{L}{k}  = \frac{C"}{k} \\C" = L

A = \frac{L}{k}  - \frac{L}{k} e^{kt}

So, D = R - A =

D = \frac{L}{k} - \frac{L}{k}  - \frac{L}{k} e^{kt}\\D = \frac{L}{k} e^{kt}

when t = 0(at initial time), the initial value of D =

D = \frac{L}{k} e^{kt}\\D = \frac{L}{k} e^{k0}\\D = \frac{L}{k} e^{0}\\D = \frac{L}{k}

4 0
3 years ago
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