Question

An airplane descends during the last hour of it's flight to prepare for landing. It's altitude changes at an average of -0.15 km per minute for those 60 minutes. Write an expression to represent the total change in the airplane's elevation. ( plz answer, will give brainliest )

Answer 1

Answer:

-.15 km/ minute * 60 minutes

-9 km

Step-by-step explanation:

The rate is -.15 km per minute

We have 60 minutes

distance = rate  times time

change in elevation is the same as the distance change

change in elevation = -.15 km/ minute * 60

   change in elevation =-9 km

Answer 2

Answer:

(0.15 km/min) * (60 min)

Step-by-step explanation:

We see that the plane descends 0.15 kilometres every minute over the span of 60 minutes.

Use the distance-rate-time formula: d = rt, where d is the distance, r is the rate, and t is the time.

Here, our rate is r = 0.15 km/min and our time is t = 60 minutes. Then the total change in elevation is:

d = rt

d = 0.15 * 60 = 9 km

Note that we disregard the negative sign from -0.15 km/min because the question is asking for the change in elevation. Change is never a negative value.

Hence, the expression will be: 0.15 * 60, which simplifies to 9 km.

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