Answer:
The dust does have any third charge.
Explanation:
In the context, the glass rod gets positively charged and so it induces a negative charge on the dust particles which are neutral. Thus the face of the dust particle which is near to the rod becomes negative charge and the opposite face of the dust gets equal positive charge and hence it ensures the neutrality of the dust particle but still being attracted to the glass rod.
And in the case of the negatively charged silk, the silk induces or gives positive charge to the dust particle which is neutral in charge. The face which is near to the silk gets positive charge and the other face becomes negative charge, again ensuring its neutrality and being attracted to the glass rod.
This shows how both positive charged rod and negatively charged silk attracts the neutral dust particle.
Answer:
The current flowing through the 4Ω resistor is;
C. 2.0 A
Explanation:
In the given figure, we have;
The series resistors in the bridge = 8Ω, and 4Ω are in series and 20Ω and 10Ω are in series
The sum of each of the series resistors are;
R₁ = 8Ω + 4Ω = 12Ω
R₂ = 20Ω + 10Ω = 30Ω
The equivalent resistors of the series resistors, R₁ and R₂ are parallel to each other
The current flowing through the 4Ω resistor = The current in R₁ = I₁
By the current divider rule, we have;
Therefore, I₁ = 2.0 A
The current flowing through the 4Ω resistor = I₁ = 2 A
First one heat, the second one is radiation and the third is radiated ;)
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