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lozanna [386]
2 years ago
9

The momentum of a 0.1 kg object traveling at 2000 m/s is 20,000 kg·m/s. True or False

Physics
1 answer:
Alina [70]2 years ago
3 0

That's false.  

The definition of momentum is (mass) x (speed), so they must be multiplied.

"20,000 kg-m/s" has the correct units resulting from multiplication, but the number could only be the result of division.

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Una ambulancia se aleja de una persona en línea recta a razón de 30 m/s. Si la sirena
saul85 [17]

Answer:

f_o=331.046Hz

Explanation:

Use Doppler effect equation:

The Doppler effect is a physical phenomenon where an apparent change in wave frequency is presented by a sound source with respect to its observer when that same source is in motion. The general equation is given by:

f_o=f_s\frac{v\pm v_o}{v\mp v_s} \\\\Where:\\\\f_s=Actual\hspace{3}frequency\hspace{3}of\hspace{3}the\hspace{3}sound\hspace{3}waves\\f_o=Observed\hspace{3}frequency\\v=Speed\hspace{3}of\hspace{3}the\hspace{3}sound\hspace{3}waves\\v_o=Velocity\hspace{3}of\hspace{3}the\hspace{3}observer\\v_s=Velocity\hspace{3}of\hspace{3}the\hspace{3}source

  • When the observer moves towards the source v_o is positive.
  • When the observer moves away from the source v_o is negative.
  • When the source moves towards the observer v_s is negative.
  • When the source moves away from the observer v_s is positive.

Since the problem don't give us aditional information let's assume:

v=343m/s

Which is the speed of sound in air.

And using the information provided by the problem:

v_s=30m/s\\v_o=0\\f_s=360Hz

f_o=f_s\frac{v}{v+v_s} =360*\frac{343}{343+30} =331.0455764\approx 331.046Hz

The frequency perceived by the person is 331.046Hz

<em><u>Translation:</u></em>

<em><u></u></em>

Usa la ecuación del Efecto Doppler:

El efecto Doppler es un fenómeno físico en el que una fuente de sonido presenta un cambio aparente en la frecuencia de onda con respecto a su observador cuando esa misma fuente está en movimiento. La ecuación general viene dada por:

f_o=f_s\frac{v\pm v_o}{v\mp v_s} \\\\Donde:\\\\f_s=Frecuencia\hspace{3}real\hspace{3}de\hspace{3}las\hspace{3}ondas\hspace{3}sonoras\\f_o=Frecuencia\hspace{3}observada(percibida)\\v=Velocidad\hspace{3}de\hspace{3}las\hspace{3}ondas\hspace{3}sonoras\\v_o=Velocidad\hspace{3}del\hspace{3}observador\\v_s=Velocidad\hspace{3}de\hspace{3}la\hspace{3}fuente

  • Cuando el observador se mueve hacia la fuente v_o es positivo.
  • Cuando el observador se aleja de la fuente es v_o negativo.
  • Cuando la fuente se mueve hacia el observador v_s es negativa.
  • Cuando la fuente se aleja del observador v_s es positiva.

Como el problema no nos da información adicional, supongamos que:

v=343m/s

La cuál es la velocidad del sonido en el aire.

Y utilizando la información proporcionada por el problema:

v_s=30m/s\\v_o=0\\f_s=360Hz

f_o=f_s\frac{v}{v+v_s} =360*\frac{343}{343+30} =331.0455764\approx 331.046Hz

La frecuencia percibida por la persona es 331.046Hz

5 0
3 years ago
Motion equation of object is
Ganezh [65]

Take the derivative to find the velocity of the object:

v=\dfrac{\mathrm dx}{\mathrm dt}=-12+6t

The object stops when v=0:

-12+6t=0\implies6t=12\implies t=2

so the answer is E.

5 0
3 years ago
Please help on this one?
Maru [420]
The correct answer for this problem is c
3 0
3 years ago
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How can two tectonic plates move relative to each other
yarga [219]
They are doing the transform type of tectonic plate movement. This is a process where the plates move sideways. But they move at a rate of a few inches a year. Did that help you?
7 0
3 years ago
When Trinity pulls on the rope with her weight, Newton's Third Law of Motion tells us that the rope will _____
Bingel [31]

When Trinity pulls on the rope with her weight, Newton's Third Law of Motion tells us that the rope will <u>"pull back".</u>


Newton's third law of motion expresses that, at whatever point a first question applies a power on a second object, the first object encounters a power meet in extent however inverse in heading to the power that it applies.  

Newton's third law of movement reveals to us that powers dependably happen in sets, and one question can't apply a power on another without encountering a similar quality power consequently. We once in a while allude to these power matches as "action-reaction" sets, where the power applied is the activity, and the power experienced in kind is the response (despite the fact that which will be which relies upon your perspective).

6 0
3 years ago
Read 2 more answers
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