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3 years ago

9

Assume that the force of gravitational attraction between two objects is 6 units.

1 answer:

pentagon [3]3 years ago

8 0

Answer:

dk

Explanation:

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Three point charges are positioned on the x axis. If the charges and corresponding positions are +32 µC at x = 0, +20 µC at x =

Crank

Answer:

Fnet = 12 N

Explanation:

Force on a point charge due to another point charge = kq1q2 / d^2

Force on +32uC = due to + 20uC + due to -60uC

where uC = 1 x 10^-6 C and k = 9 x 10^9 N m^2 / C^2

Net Force =

$= \frac{1}{4\pi \epsilon _0} [\frac{32 \times 10^-^6 \times60\times10^-^6}{(60/100)^2}-\frac{32 \times 10^-^6 \times20\times10^-^6}{ (40/100)^2} ]$

$F_{net}=9 \times10^9\times 10^-^1^2[\frac{32\times60\times10^4}{60\times60} -\frac{32\times20\times10^4}{40\times40} ]$

$=90[32(\frac{80-60}{60\times 80} )]\\\\=90\times32\times0.004167\\\\=12N$

Fnet = 12 N

8 0

4 years ago

A solid circular shaft and a tubular shaft, both with the same outer radius of c=co = 0.550 in , are being considered for a part

Norma-Jean [14]

Answer:

The power for circular shaft is 7.315 hp and tubular shaft is 6.667 hp

Explanation:

<u>Polar moment of Inertia</u>

$(I_p)s = \frac{\pi(0.55)4}2$

= 0.14374 in 4

<u>Maximum sustainable torque on the solid circular shaft</u>

$T_{max} = T_{allow} \frac{I_p}{r}$

= $(14 \times 10^3) \times (\frac{0.14374}{0.55})$

= 3658.836 lb.in

= $\frac{3658.836}{12}$ lb.ft

= 304.9 lb.ft

<u>Maximum sustainable torque on the tubular shaft</u>

$T_{max} = T_{allow}( \frac{Ip}{r})$

= $(14 \times10^3) \times ( \frac{0.13101}{0.55})$

= 3334.8 lb.in

= $(\frac{3334.8}{12} )$ lb.ft

= 277.9 lb.ft

<u>Maximum sustainable power in the solid circular shaft</u>

$P_{max} = 2 \pi f_T$

= $2\pi(2.1) \times 304.9$

= 4023.061 lb. ft/s

= $(\frac{4023.061}{550})$ hp

= 7.315 hp

<u>Maximum sustainable power in the tubular shaft</u>

$P _{max,t} = 2\pi f_T$

= $2\pi(2.1) \times 277.9$

= 3666.804 lb.ft /s

= $(\frac{3666.804}{550})$ hp

= 6.667 hp

7 0

3 years ago

Which of these is an example of energy transfer by radiation?

andrezito [222]

Answer:

Hands rubbed together to become warm

6 0

3 years ago

Read 2 more answers

Two charged concentric spheres have radii of 0.008 m and 0.018 m. The charge on the inner sphere is 3.62 10-8 C and that on the

Alekssandra [29.7K]

Answer:

The electric field is $E = 2.2625 *10^{6} \ N/C$

Explanation:

From the question we are told that

The radius of the inner sphere is $r_1 = 0.008\ m$

The radius of the outer sphere is $r _2 = 0.018 \ m$

The charge on the inner sphere is $q_1 = 3.62 *10^{-8} \ C$

The charge on the outer sphere is $q_2 = 1.62 *10^{-8} \ C$

The position from the origin is $d = 0.012 \ m$

Generally the electric field is mathematically represented as

$E = \frac{k (q_1 )}{ r^2}$

The reason for using $q_1$ for the calculation is due to the fact that the position considered is greater than the $r_1$ but less than $r_2$

Here k is the Coulomb constant with value $k = 9*10^{9} \ kg\cdot m^3\cdot s^{-4} \cdot A{-2}$

So

$E = \frac{9*10^9 (3.62 *10^{-8}}{0.012^2}$

$E = 2.2625 *10^{6} \ N/C$

6 0

3 years ago

Compare and contrast the average kinetic energy of 0.5 L of coffee at 34ÁC,

Andre45 [30]

Compared to coffee at room temperature, the molecules of the coffee at 34°C will be moving faster and colliding with one another more frequently.

6 0

3 years ago