Answer:
i think its C hope this is rhight have a good day
Explanation:
Most likely it will reflect off the surface and create a fire
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Below is the solution:
<span>T2cos(30) - T1cos(50) = 0
</span><span>T1sin(50) + T2sin(30) - (75 lbs.)*(accel. grav.) = 0
</span><span>T2cos(30) - T1cos(50) = 0 --> T1 = T2cos(30)/cos(50)
</span>
<span>T1sin(50) + T2sin(30) - (75 lbs.)*(accel. grav.) = 0
</span>(<span>T2cos(30)/cos(50))sin(50) + T2sin(30) - (75 lbs.)*(accel. grav.) = 0 --> Solve for T2
</span><span>T1 = -T1cos(50)i + T1sin(50)j
T2 = T2cos(30)i + T2sin(3)j
</span>
<span>(T2cos(30)/cos(50))sin(50) + T2sin(30) - (75 lbs.)*(accel. grav.) = 0 -->
T2[(cos(30)/cos(50))sin(50) + sin(30)] = 75*(grav) -->
T2 = 75*grav/ [(cos(30)/cos(50))sin(50) + sin(30)]
</span>
<span> T2 = 1566.49 </span>
Answer:
31.28m/s
Explanation:
We can use the third key equation of accelerated motion
Δd = viΔt+1/2aΔt^2
subtitute in the values we know
41.6 = vi(1.89)+1/2(-9.8)(1.89)^2
41.6 = vi(1.89) - 17.52
59.12 = vi(1.89)
vi = 31.28
