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diamong [38]
3 years ago
5

Previously, an organization reported that teenagers spent 4.5 hours per week, on average, on the phone. The organization thinks

that, currently, the mean is higher. Fifteen randomly chosen teenagers were asked how many hours per week they spend on the phone. The sample mean was 4.75 hours with a sample standard deviation of 2.0. Conduct a hypothesis test, the Type I error is:
a. to conclude that the current mean hours per week is higher than 4.5, when in fact, it is higher
b. to conclude that the current mean hours per week is higher than 4.5, when in fact, it is the same
c. to conclude that the mean hours per week currently is 4.5, when in fact, it is higher
d. to conclude that the mean hours per week currently is no higher than 4.5, when in fact, it is not higher
Mathematics
1 answer:
hammer [34]3 years ago
6 0

Answer:

Type I error is : to conclude that the current mean hours per week is higher than 4.5, when in fact, it is the same.

Step-by-step explanation:

We are given that an organization reported that teenagers spent 4.5 hours per week, on average, on the phone. The organization thinks that, currently, the mean is higher. For this fifteen randomly chosen teenagers were asked how many hours per week they spend on the phone. The sample mean was 4.75 hours with a sample standard deviation of 2.0 hours.

Let Null Hypothesis, H_0 : \mu \leq 4.5 hours {means that the current mean hours per week is less than or equal to 4.5}

Alternate Hypothesis, H_1 : \mu > 4.5 hours {means that the current mean hours per week is higher than 4.5}

<em>Now, T</em><u><em>ype I error states that</em></u><em> : Probability of rejecting null hypothesis given the fact that it was true or Rejecting the true null hypothesis.</em>

<u>So, according our question;</u>

Type I error is to conclude that the current mean hours per week is higher than 4.5, when in fact, it is the same.

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Lucy studies 1 hour less than twice the number of hours a week that rose studies. Lucy studies for 11 hours a week. How many hou
Lana71 [14]

Answer:

6.

Step-by-step explanation:

Lucy studies one less (-1) than twice the number of hours a week that rose studies (2 * R), lucy studies 11 hours a week. What we do is add 1 hour to lucy's 11, to get 12, then divide by 2 as lucy studies twice the hours. 12 / 2 = 6.

3 0
3 years ago
Read 2 more answers
The product of three and a number decreased by ten is thirteen
monitta

Answer:

3x - 10 = 13 would be the verbal expression where x = a number

Hope this helps!

5 0
2 years ago
How in the world do you do this problem<br> (-1,0)<br> y+__= 4(x+2)
WARRIOR [948]
X = 0 y =-1 because you have to have to find numbers to replace x & y.
3 0
3 years ago
Show that if the vector field F = Pi + Qj + Rk is conservative and P, Q, R have continuous first-order partial derivatives, then
olchik [2.2K]

Answer:

It is proved that \frac{\partial P}{\partial y}=\frac{\partial Q}{\partial x}, \frac{\partial P}{\partial z}=\frac{\partial R}{\partial x}, \frac{\partial Q}{\partial z}=\frac{\partial R}{\partial y}

Step-by-step explanation:

Given vector field,

F=P\uvec{i}+Q\uvec{j}+R\uvec{k}

Where,

P=f_x=\frac{\partial f}{\partial x}, Q=f_y=\frac{\partial f}{\partial y}, R=f_z=\frac{\partial f}{\partial z}

To show,

\frac{\partial P}{\partial y}=\frac{\partial Q}{\partial x}, \frac{\partial P}{\partial z}=\frac{\partial R}{\partial x}, \frac{\partial Q}{\partial z}=\frac{\partial R}{\partial y}

Consider,

\frac{\partial P}{\partial y}=\frac{\partial}{\partial y}(\frac{\partial f}{\partial x})=\frac{\partial^2 f}{\partial y\partial x}=\frac{\partial^2 f}{\partial x\partial y}=\frac{\partial }{\partial x}(\frac{\partial f}{\partial y})=\frac{\partial Q}{\partial x}

\frac{\partial P}{\partial z}=\frac{\partial}{\partial z}(\frac{\partial f}{\partial x})=\frac{\partial^2 f}{\partial z\partial x}=\frac{\partial^2 f}{\partial x\partial z}=\frac{\partial }{\partial x}(\frac{\partial f}{\partial z})=\frac{\partial R}{\partial x}

\frac{\partial Q}{\partial z}=\frac{\partial}{\partial z}(\frac{\partial f}{\partial y})=\frac{\partial^2 f}{\partial z\partial y}=\frac{\partial^2 f}{\partial y\partial z}=\frac{\partial}{\partial y}(\frac{\partial f}{\partial z})=\frac{\partial R}{\partial y}

Hence proved.

4 0
3 years ago
Jess will flip a two-sided coin and roll a number cube with numbers 1, 2, 3, 4, 5, 6 one time. What is the probability that the
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Answer:

1/4

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number of numbers >3=3(4,5,6)

probability=3/6=1/2

probability of drawing a head=1/2

reqd. probabilty=1/2*1/2=1/4

8 0
3 years ago
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