K+2 over 3= -7 <br> How do u solve this problem

If a diameter intersects a chord of a circle at a perpendicular, what conclusion can be made? The diameter and the chord are con

yarga [219]

Answer:

The chord is bisected ⇒ 3rd answer

Step-by-step explanation:

* Lets revise some facts in the circle to solve the problem

- A chord in a circle is the segments whose endpoints lie on the

circumference of the circle

- A diameter of a circle is a chord passes through the center of the

circle

- The diameter is the longest chord in the circle

- Any line passes through the center of the circle and perpendicular

to a chord on the circle bisects it

* Lets solve the problem

∵ The diameter of the circle passes through the center of the circle

∵ The diameter intersects a chord of a circle at a perpendicular

∴ The diameter is perpendicular to the chord

∵ Any line passes through the center of the circle and perpendicular

to a chord on the circle bisects it

∴ The diameter bisects the chord

* The chord is bisected

8 0

3 years ago

Read 2 more answers

Using a Celsius scale, water freezes at 0°C and boils at 100°C. Using a Fahrenheit scale, water freezes at 32°F and boils at 212

natulia [17]

Y= (x(9/5)) + 32; Ex: y=(100(9/5)) + 32 —> 100 x 1.8 (or 9/5) = 180–> 180 + 32= 212 F

5 0

3 years ago

Write an equation that uses partial products to multiply 8 X 64

zhuklara [117]

8 x 64 = (8 x 60) + (8 x 4)=

4 0

3 years ago

Read 2 more answers

Find the volume of a cube<br> whose surface area is 150<br> ft2?

Brrunno [24]

Given:

Surface area of cube = 150 ft²

To Find:

Volume of cube

Solution:

As here in Question we are given Surface area of cube is 150 sq. feet. So, firstly we have find the side of edge of cube. Let 'a' be the edge of the cube

We know that,

$\: \: \: \: \dashrightarrow \sf \: \: \: \: Surface \: area_{(Cube)} = 6a^2 \\ \\$

Substituting the required values,

$\: \: \: \: \dashrightarrow \sf \: \: \: \: 150 = 6a^2 \\ \\ \: \: \: \: \dashrightarrow \sf \: \: \: \: \frac{150}{6} = {a}^{2} \\ \\ \: \: \: \: \dashrightarrow \sf \: \: \: \: 25 = {a}^{2} \\ \\ \: \: \: \: \dashrightarrow \sf \: \: \: \: \sqrt{25} = a \\ \\ \: \: \: \: \dashrightarrow \sf \: \: \: \: { \underline{ \boxed{ \sf{ \pink{5 = a}}}} } \\ \\$

Edge of the cube is 5 feet

Now,

$\: \: \: \: \dashrightarrow \sf \: \: \: \: Volume = (edge)^3 \\ \\ \: \: \: \: \dashrightarrow \sf \: \: \: \: Volume = (5)^3 \\ \\ \: \: \: \:\dashrightarrow \sf \: \: \: \: {\underline{\boxed{\sf{\pink{Volume =125 \: {ft}^{3}}}}}} \\ \\$

Hence,

Volume of the cube is 125 cu. feet

7 0

2 years ago

Read 2 more answers

Can someone help me with this? i dont understand it

Inessa05 [86]

So create a box with boxes in it then ur work goes in each box
have a nice day sir/maam

3 0

3 years ago

Read 2 more answers

K+2 over 3= -7 How do u solve this problem