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-Dominant- [34]

3 years ago

8

If a random experiment consists of rolling a six-sided die 10 times, how many individual outcomes make up the sample space, and

what is the probability of getting all sixes?

2 answers:

lakkis [162]3 years ago

8 0

Answer:

The answer is D.............

Step-by-step explanation:

Pavel [41]3 years ago

5 0

Answer:

D..................i did the test

Step-by-step explanation:

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Farmer sells 6.2 kg of pears and apples at the farmers market 3/5 of this away is Paris, and the rest is apples. How many kilogr

Romashka [77]

Answer:

2.48 kg

Step-by-step explanation:

1 - ⅗ = ⅖

⅖ × 6.2 = 2.48

8 0

3 years ago

What are the numbers less than -7 and greater than -15?

Gnoma [55]

Answer:

-8,-9,-10,-11,-12,-13

Step-by-step explanation:

4 0

2 years ago

On a coordinate plane, rhombus W X Y Z is shown. Point W is at (7, 2), point X is at (5, negative 1), point Y is at (3, 2), and

Otrada [13]

Answer:

$P = 4\sqrt{13}$

Step-by-step explanation:

Given

$W = (7, 2)$

$X = (5, -1)$

$Y = (3, 2)$

$Z =(5, 5)$

Required

The perimeter

To do this, we first calculate the side lengths using distance formula

$d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2$

So, we have:

$WX = \sqrt{(5- 7)^2 + (-1 - 2)^2$

$WX = \sqrt{13}$

$XY = \sqrt{(3-5)^2 + (2--1)^2}$

$XY = \sqrt{13}$

$YZ = \sqrt{(5-3)^2 + (5-2)^2}$

$YZ = \sqrt{13}$

$ZW = \sqrt{(7 - 5)^2 + (2 - 5)^2}$

$ZW = \sqrt{13}$

The perimeter is:

$P = WX + XY + YZ + ZW$

$P = \sqrt{13}+\sqrt{13}+\sqrt{13}+\sqrt{13}$

$P = 4\sqrt{13}$

5 0

3 years ago

Read 2 more answers

Casey uses some of his savings on batting practice. the cost of renting a batting cage for 1 hour is $6. he rents a cage for 9 h

sammy [17]

It 54 thank you welcome you

5 0

3 years ago

PLEASE HELP! I ACCIDENTALLY STARTED THIS QUIZ TOO EARLY!

telo118 [61]

Answer:

inside

√((5-(-5))^2+((-24)-(-8))^2)=√(10^2+16^2)=√356＜25

4 0

2 years ago