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stiv31 [10]
3 years ago
10

Solve and graph the solutions to the number line

Mathematics
1 answer:
Mars2501 [29]3 years ago
6 0
GO TO THIS WEB SITE AND PUT IN THE TWO NUMBERS THAT YOU NEED TO DO 
https://static.k12.com/calms_media/media/175000_175500/175477/3/ac2a1c4b8c535c5d05921716e38de41a349d...
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Given the equation y = 3x − 4, what is the value of y when x = 4?
Marat540 [252]

Answer:

C) 8

Step-by-step explanation:

y=3*4-4

y=12-4

y=8

5 0
3 years ago
Joe determined the mass of 2 boxes using a scale. Since the cost of each box is the same, Joe would like to choose the box with
Naddika [18.5K]

Answer:

32.012 kg < 32.02 kg

Step-by-step explanation:

32.012 kg < 32.02 kg

7 0
3 years ago
Find the x- and y- intercepts of parabola y=5x^2-16x+10
____ [38]

Y-INTERCEPT

y = 5x^2 - 16x + 10

The y-intercept is where the equation/curve/parabola cosses the y-axis.

The y-axis is where x = 0. (The x-axis is where y = 0)

To find the y-intercept:

\text{y-axis} \rightarrow \text{x = 0} \rightarrow y = 5(0)^2 -16(0) + 10 = 10

The y-intercept must be at (0, 10)

X-INTERCEPT (ROOTS/SOLUTIONS)

y = 5x^2 - 16x + 10\\\text{make it equal 0}\\y = 0\\\therefore 5x^2 - 16x + 10 = 0

We need to use the quadratic formula

The quadratic formula helps us find what values of x make the equation = 0

Quadratic formula: x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

x=\frac{-(-16) + \sqrt{(-16)^2-4(5)(10)}}{2(5)}\\\\x = \frac{16 + \sqrt{256-200}}{10}\\x = \frac{16 + \sqrt{56}}{10}\\x = \frac{16 + 2\sqrt{14}}{10}\\x = \frac{8 + \sqrt{14}}{5}\\\\\\x=\frac{-(-16) - \sqrt{(-16)^2-4(5)(10)}}{2(5)}\\\text{doing the same thing...}\\\text{end up with...}\\x = \frac{8 - \sqrt{14}}{5}\\

The x-intercepts are at:

(\frac{8 + \sqrt{14}}{5}, 0)\\(\frac{8 - \sqrt{14}}{5}, 0)

5 0
2 years ago
Help ASAP!!!!!!!!!!!!!!!
Advocard [28]
Answers D. and E. are correct.
I think that B might also be correct, I hope This helps.
7 0
2 years ago
Math math math!!!! :/
vekshin1

the answer is B your welcome

6 0
3 years ago
Read 2 more answers
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