Answer and Explanation:
As per the data given in the question,
Sum of the all mean value = 151
Average of the mean value = 151 ÷ 15 = 10.067
Similarly, Sum of the all given range = 151
Average of given range value = 151÷ 15 = 10.067
Control charts for the mean and the range, using the original 15 samples :
Upper control limit(UCL) - Lower control limit(LCL) for X bar is
= 10.067 + A2 × R bar
= 10.067 + (0.223 × 10.067)
= 12.31
LCL - UCL for X bar is
= 10.067 - A2 × R bar
= 10.067 -(0.223 × 10.067)
= 7.82
Set up the R-chart by specifying the center line and three-sigma control limits below :
UCLr = D4 × r
= 1.653 × 10.07
= 16.65
r = 10.067
= 10.07
LCLr = D3 × r
= 0.347 ×10.07
= 3.49
Answer:
Hahahahahahahha is it that much difficult
Answer: The saving rate is 0.30
Explanation:
The Golden Rule savings rate is referred to as the rate of savings which maximizes steady state level or growth of consumption.
Let k be the capital/labour ratio (i.e., capital per capita), y be the resulting per capita output ( y = f(k) ), and s be the savings rate. The steady state is referred to as a situation in which per capita output is unchanging, which implies that k be constant. This requires that the amount of saved output be exactly what is needed to one quip any additional workers and two replace any worn out capital.
In a steady state, therefore: sf(k)=(n+d)k
Growth rate of output =3%
Depreciation rate= 4%
Capital output ratio is (K/Y)
= 2.5
Begin the steady state condition:
S= ( σ + n + g) (k/Y)
S= (0.03+0.04) (2.5)
S= 0.175
Golden rule steady state
MPK= (0.03+0.04)= 0.07
Capital output ratio=
K/Y= Capital share / MPK
K/Y= 0.3/0.07
K/Y= 4.29
In the golden state, the capital output ratio is equal to 4.29 in comparison to the current capital ratio 2.5.
The saving rate consistent with the steady growth rate
S= ( σ + n + g) (k/Y)
S= (0.03 +0.04) (4.29)
S= 0.30
The saving rate that is consistent with the steady growth rate is 0.30
An experiment that could test the Premack differential probability rule is as per the following; the kids are given two reaction choices, one for playing pinball machine and another for eating confection and these practices are evaluated to figured out which is more plausible for every kid. A portion of the youngsters who discovered to favor one movement. In the second period of the trial, the testing of the youngsters was directed with one oF the two systems. In the primary strategy, eating was a fortifying reaction while playing pinball was the instrumental reaction implying that the youngsters played pinball keeping in mind the end goal to eat the confection.
