Answer:

Now we can find the limits in order to determine outliers like this:


So for this case the left boundary would be 3, if a value is lower than 3 we consider this observation as an outlier
b. 3
Step-by-step explanation:
For this case we have the following summary:
represent the minimum value
represent the first quartile
represent the median
represent the third quartil
represent the maximum
If we use the 1.5 IQR we need to find first the interquartile range defined as:

Now we can find the limits in order to determine outliers like this:


So for this case the left boundary would be 3, if a value is lower than 3 we consider this observation as an outlier
b. 3
This question is all about dimensional analysis. The whole idea behind dimensional analysis is that you multiply a starting value with different conversion factors to cancel out units you don't want to tern the value into the units that you do want. The conversion for yards to feet can be written as 3 feet/yard (this is the conversion factor it can be written as 3feet/1yard or 1yard/3feet, it depends on what you are starting with). If you start out with yards and and want to go to feet you have to multiply the number of yards by 3feet/yard so that the yards cancel out leaving you with feet. If start out with feet and want to go to yards you divide the number of feet by 3feet/yard so that the feet cancel out and you are left with yards.
In your question Tom is trying to go from feet to yards. Therefore he has to divide the number of feet by 3feet/yard to get feet to cancel out. His mistake was that he multiplied by 3feet/yard instead of divide by 3feet/yard. The correct way do it is divide 379 feet by 3feet/yard to get 126.33 yards.
Let me know if anything is unclear to you in the comments. This is a very important skill to learn since this is the basis of many high school and college science classes.
I hope this helps.
A dilation can elongate or diminish a figure. It can
create an image the same as the original by using a scale factor. The scale
factor of a dilation is the ratio of corresponding side lengths. To
dilate a polygon, multiply the coordinates of each vertex by the scale
factor k and connect the vertices.
Answer: Its factored form will be

Step-by-step explanation:
Since we have given that

So, we need to factor ,

Now,

Now, by hit and trial method, we put n=1,


So, n-1 is also factor of p(n).
Now,

So, its factored form will be

Answer:
64
Step-by-step explanation:
<em>[using calculus] </em>When the function h(t) reaches its maximum value, its first derivative will be equal to zero (the first derivative represents velocity of the ball, which is instantaneously zero). We have
, which equals zero when
. The ball therefore reaches its maximum height when t = 1.5. To find the maximum height, we need to find h(1.5), which is 64 feet.
<em>[without calculus] </em>This is a quadratic function, so its maximum value will occur at its vertex. The formula for the x-coordinate of the vertex is -b/2a, so the maximum value occurs when t = -48/(2*16), which is 1.5. The maximum height is h(1.5), which is 64 feet.