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4 years ago

What is the slope intercept form of (4,-3) slope of 1/4

1 answer:

4 0

Y = mx + b
slope(m) = 1/4
(4,-3)...x = 4 and y = -3
now we sub and find b, the y int
-3 = 1/4(4) + b
-3 = 1 + b
-3 - 1 = b
-4 = b

so ur equation is : y = 1/4x - 4

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15 cm 16.6 cm area cm2

Ymorist [56]

Answer:

357.1573 (If you don't round)

Step-by-step explanation:

To find area of a rectangle is to multiply length by width, which in this situation would be 15 by 16.6, which is equal to 249. Next, we need to add this to the area of the semicircle. The area of a semicircle is equal to 1/2 * pi * radius^2 (Because a semicircle is half a circle and a circle's area is pi * radius^2). The radius is equal to half the diameter, which in this case is 16.6. 16.6/2 = 8.3, so the radius is 8.3. If we plug this into the equation, we get that 108.1573 is the area of the circle (If you use 3.14 as pi). 108.1573 + 249 is equal to 357.1573.

7 0

3 years ago

Coffee café mix 90 pounds of coffee that cost six dollars per pound the types of coffee used to make this makes you cost seven d

Troyanec [42]

Answer:

y = 60

Step-by-step explanation:

From the information we get:

x quantity of 4 dollars coffee used in the mix

y quantity of 7 dollars coffee used in the mix

For the quantity of coffee to be sold a 7 $/pound ( 90 pounds)

Then 6*90 = 540 $

Therefore

x + y = 90 and

4*x + 7*y = 540

A two equations system we solve for x and y

y = 90 - x

4*x + 7* ( 90 - x ) = 540

4*x + 630 - 7*x = 540

- 3*x = - 90

x = 30 pounds and

y = 90 - 30

y = 60

We should use 60 pounds of the seven $ coffee

4 0

3 years ago

A point H is 20m away from the foot of a tower on the same horizontal ground. From the point H, the angle of elevation of the po

astra-53 [7]

Answer:

a. See Attachment 1

b. $PT = 12.3\ m$

c. $HT = 31.1\ m$

d. $OH = 28.4\ m$

Step-by-step explanation:

Calculating PT

To calculate PT, we need to get distance OT and OP

Calculating OT;

We have to consider angle 50, distance OH and distance OT

The relationship between these parameters is;

$tan50 = \frac{OT}{20}$

Multiply both sides by 20

$20 * tan50 = \frac{OT}{20} * 20$

$20 * tan50 = OT$

$20 * 1.1918 = OT$

$23.836 = OT$

$OT = 23.836$

Calculating OP;

We have to consider angle 30, distance OH and distance OP

The relationship between these parameters is;

$tan30 = \frac{OP}{20}$

Multiply both sides by 20

$20 * tan30 = \frac{OP}{20} * 20$

$20 * tan30 = OP$

$20 * 0.5774= OP$

$11.548 = OP$

$OP = 11.548$

$PT = OT - OP$

$PT = 23.836 - 11.548$

$PT = 12.288$

$PT = 12.3\ m$ (Approximated)

--------------------------------------------------------

Calculating the distance between H and the top of the tower

This is represented by HT

HT can be calculated using Pythagoras theorem

$HT^2 = OT^2 + OH^2$

Substitute 20 for OH and $OT = 23.836$

$HT^2 = 20^2 + 23.836^2$

$HT^2 = 400 + 568.154896$

$HT^2 = 968.154896$

Take Square Root of both sides

$HT = \sqrt{968.154896}$

$HT = 31.1\ m$ (Approximated)

--------------------------------------------------------

Calculating the position of H

This is represented by OH

See Attachment 2

We have to consider angle 50, distance OH and distance OT

The relationship between these parameters is;

$tan50 = \frac{OH}{OT}$

Multiply both sides by OT

$OT * tan50 = \frac{OH}{OT} * OT$

$OT * tan50 = {OH$

$OT * 1.1918 = OH$

Substitute $OT = 23.836$

$23.836 * 1.1918 = OH$

$28.4= OH$

$OH = 28.4\ m$ (Approximated)

5 0

3 years ago

To solve the equation 2x - 6 = 14, first

Anna [14]

2x - 6 = 14

Add 6 to both sides to isolate the x

2x = 20

Divide 2 to both sides since x is multipled to x

x = 10

To check your work plug 10 into the equation

2(10) -6 = 14

20 - 6 = 14

14 = 14

and it works

8 0

3 years ago

Read 2 more answers

Does anybody know what these type of problems are called please help

zavuch27 [327]

In the figure above, you are given the value of a start equal to 10 and the clover equal to 5. You are given a pole with three strings divided equally, the center string is tied to a wall and the two other strings carry either of the items. The first string has two stars and one clover which will have a total of 25 and the other string has one star and three clovers which will have a total of 25. The name of this type of problem is addition. Overall, the total weight of the items is 50.

4 0

3 years ago