3 hundredths + 4 hundredths =

Greg’s home is 1.8 miles from his school. There is a music store

elena55 [62]

Answer: Distance from school to music store: 2.8/2=1.4.

1.4 miles

Step-by-step explanation:

4 0

3 years ago

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Convert 6 2/3 to an improper fraction

mixas84 [53]

Answer:

= 20/3

Step-by-step explanation:

Convert using a b/c = a*c+b / c

6 2/3 = 6*3+2 / 3

Simplify:

20/3

3 0

3 years ago

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Question 1 options:Residents in Portland, Oregon think that their city has more rainfall than Seattle, Washington. To test this

dimaraw [331]

Answer:

There is no enough evidence to to support the claim that Portland has more average yearly rainfall than Seattle.

Being μ1: average rainfall in Portland, μ2: average rainfall in Seattle, the null and alternative hypothesis are:

$H_0: \mu_1-\mu_2=0\\\\H_a:\mu_1-\mu_2 > 0$

P-value = 0.1290

As the P-value is bigger than the significance level, the effect is not significant and the null hypothesis failed to be rejected.

Step-by-step explanation:

We have to test the hypothesis of the difference between means.

The claim is that Portland has more average yearly rainfall than Seattle.

Being μ1: average rainfall in Portland, μ2: average rainfall in Seattle, the null and alternative hypothesis are:

$H_0: \mu_1-\mu_2=0\\\\H_a:\mu_1-\mu_2 > 0$

The significance level is 0.10.

The sample for Portland, of size n1=45, has a mean of M1=37.50 and standard deviation of s1=1.82.

The sample for Seattle, of size n1=35, has a mean of M1=37.07 and standard deviation of s1=1.68.

The difference between means is:

$M_d= M_1-M_2=37.50-37.07=0.43$

The standard error for the difference between means is:

$s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{1.82^2}{45}+\dfrac{1.68^2}{35}}=\sqrt{ 0.0736+0.0688 }=\sqrt{0.1424}\\\\\\s_{M_d}=0.3774$

We can calculate the t-statistic as:

$t=\dfrac{M_d-(\mu_1-\mu_2)}{s_{M_d}}=\dfrac{0.43-0}{0.3774}=1.1393$

The degrees of freedom are:

$df=n1+n2-2=45+35-2=78$

Then, the p-value for this one-tailed test with 78 degrees of freedom is:

$P-value=P(t>1.1393)=0.1290$

As the P-value is bigger than the significance level, the effect is not significant and the null hypothesis failed to be rejected.

There is no enough evidence to to support the claim that Portland has more average yearly rainfall than Seattle.

7 0

3 years ago

About what percent of the data are greater than 20?

Pachacha [2.7K]

About 25 percent of the data are greater than 20.(option a)

About 50 percent of the data are less than 15. (option b)

20 is wrongly interpreted as the median. 20 is the third quartile. The data between 11 and 20 is 50%.

<h3>How can a box-and-whisker plot be interpreted?</h3>

A box plot is used to study the distribution and level of a set of scores. The scores are distributed into 4 groups. Each group has a value of 25%

The box plot consists of two whiskers and a box. The first whisker represent the minimum value. The second whisker represents the maximum number.

On the box, the first line to the left represents the lower (first) quartile. 25% of the score represents the lower quartile. The next line on the box represents the median. 50% of the score represents the median. The third line on the box represents the upper (third) quartile. 75% of the scores represents the upper quartile.

20 is the third quartile. Score greater than 20 is 25% (100% - 75%)

15 is the median. Scores less than 15 is 50% (100 - 50%),

To learn more about box plots, please check: brainly.com/question/27215146

#SPJ1

3 0

1 year ago

Suppose we spin the following spinner with the first spin giving the numerator and the second spin giving the denominator of a f

fgiga [73]

Answer:6,7,8,9x4

Step-by-step explanation:

the purpose is to solve th equation5789x4

6 0

1 year ago