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allochka39001 [22]
3 years ago
11

Juanita and Samuel are planning a pizza party. They order a rectangle sheet pizza that measures 21 inches by 36 inches.?They tel

l the pizza maker not to cut it because they want to cut it themselves. All pieces of pizza must be square with none left over. What is the side length of the largest square pieces into which Juanita and Samuel can cut the pizza? How many pieces of this size can be cut?
Mathematics
1 answer:
saveliy_v [14]3 years ago
7 0
First, find the total area of pizza. The area of a rectangle is length times width. 

Area = 21 x 36 = 756 sq. inches

Now, we must divide the total area with the largest square possible without any excess. So, we equate the area of the pizza to area of square:

A = s² = 756
s = 6 √21

Hence, the largest piece square possible has a side of 6 inches. Then, we divide the total area of the pizza by the area of each square piece to find the number of pieces;

756/6² = 21

Thus, there would be 21 pieces of 6-in square piece of pizza.
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Answer:

a) 0.283  or 28.3%

b) 0.130 or 13%

c) 0.4 or 40%

d) 30.6 mm

Step-by-step explanation:

z-score of a single left atrial diameter value of healthy children can be calculated as:

z=\frac{X-M}{s} where

  • X is the left atrial diameter value we are looking for its z-score
  • M is the mean left atrial diameter of healthy children (26.7 mm)
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Then

a) proportion of healthy children who have left atrial diameters less than 24 mm

=P(z<z*) where z* is the z-score of 24 mm

z*=\frac{24-26.7}{4.7} ≈ −0.574

And P(z<−0.574)=0.283

b) proportion of healthy children who have left atrial diameters greater than 32 mm

= P(z>z*) = 1-P(z<z*) where z* is the z-score of 32 mm

z*=\frac{32-26.7}{4.7} ≈ 1.128

1-P(z<1.128)=0.8703=0.130

c) proportion of healthy children have left atrial diameters between 25 and 30 mm

=P(z(25)<z<z(30)) where z(25), z(30) are the z-scores of 25 and 30 mm

z(30)=\frac{30-26.7}{4.7} ≈ 0.702

z(25)=\frac{25-26.7}{4.7} ≈ −0.362

P(z<0.702)=0.7587

P(z<−0.362)=0.3587

Then P(z(25)<z<z(30)) =0.7587 - 0.3587 =0.4

d) to find the value for which only about 20% have a larger left atrial diameter, we assume

P(z>z*)=0.2 or 20% where z* is the z-score of the value we are looking for.

Then P(z<z*)=0.8 and z*=0.84. That is

0.84=\frac{X-26.7}{4.7}  solving this equation for X we get X=30.648

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I think the answer is m=3

Step-by-step explanation:

Hope this helps :D

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86.436 divided by 12 equals 7.203. 34.86 divided by 4 equals 8.715. 5.87 divided by 15 equals 0.38.
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