The required matrix is:
![\left[\begin{array}{ccc}-25&17&0\\8&-1&3\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-25%2617%260%5C%5C8%26-1%263%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
We need to apply elementary row operation -2R₂+3R₁ tothe matrix:
![A=\left[\begin{array}{ccc}-3&5&2\\8&-1&3\\\end{array}\right]](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-3%265%262%5C%5C8%26-1%263%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Multiplying Row 2 with -2 and Row1 with 3 and adding,
-9 15 6
-16 2 -6
----------
-25 17 0
After applying this operation, Row 1 will be changed while Row 2 will remain same because we get -2R₂+3R₁ -> R₁
The required matrix is:
![\left[\begin{array}{ccc}-25&17&0\\8&-1&3\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-25%2617%260%5C%5C8%26-1%263%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Keywords: Matrices, elementary row operation
Learn more about matrices at:
#learnwithBrainly
Answer:
Sqrt32 = 4
, Sqrt28 = 2
, Sqrt12 = 2
Step-by-step explanation:
Square root of 32:
First we find the prime factors of the number by making a factor tree.
32 splits into 8 and 4.
8 splits into 4 and 2
4 splits into 2 and 2
4 splits into 2 and 2
This becomes the square root of
x
x 2. It will simplify to:
4
Square root of 28:
The prime factors of this number are:
2, and 2
This simplifies to 2
Square root of 12:
The prime factors of this are:
3, 2, 2
This simplifies to:
2
-1 is your x intercept so the first point is going to be at (0,-1) and from there go up 1 and over to the right 2 and mark another point and so one
Answer:
I think the answer is negative five (-5)