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Alisiya [41]
3 years ago
12

Is zinc bromide and ZnBr2 an ionic bond

Chemistry
1 answer:
AveGali [126]3 years ago
6 0
YES IONIC BOND TAKES PLACE BETWEEN A METAL AND NON METALS BROMINE IS A NON METAL WHILE ZINC IS A TRANSITION METAL
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Hoochie [10]

The compound : C₄₀H₄₄N₄O

<h3>Further explanation</h3>

The empirical formula is the smallest comparison of atoms of compound =mole ratio of the components

The principle of determining empirical formula

• Determine the mass ratio of the constituent elements of the compound.  

• Determine the mole ratio by dividing the percentage by the atomic mass

The mol ratio of composition : C : H : N : O

\tt \dfrac{80.66}{12}\div \dfrac{7.39}{1}\div \dfrac{9.39}{14}\div \dfrac{2.68}{16}\\\\6.722\div 7.39\div 0.671\div 0.1675\rightarrow divide~by~smallest(0.1675)\\\\40\div 44\div 4\div 1

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3 years ago
I NEED ANSWER ASAP Which of the following statements is true for a scientific theory? It is a well-tested hypothesis. It is veri
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Answer:

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7 0
3 years ago
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The densevapor iodinee heptafluoride reacts rapidly with water to give a mixture of periodic acid and hydrofluoric acid .
erma4kov [3.2K]

Explanation:

When iodine heptafluoride reacts rapidly with water to give a mixture of periodic acid and hydrofluoric acid. Reaction equation for the same is as follows.

       IF_{7} + 6H_{2}O \rightarrow H_{5}IO_{6} + 7HF

As it is given that there are 3.72 \times 10^{-2} moles of iodine heptafluoride are present. Molar mass of IF_{7} is 259.9 g/mol. Molar mass of HIO_{4} is 227.94 g/mol and molar mass of HF is 20.01 g/mol.

Now, according to the reaction equation 3.72 \times 10^{-2} M IF_{7} gives 3.72 \times 10^{-2} M H_{5}IO_{6}.

Also, the volume is given as 795 ml or 0.795 L (as 1 mL = 0.001 L).

Hence, calculate the concentration of H_{5}IO_{6} into the solution as follows.

              Concentration = \frac{\text{no. of moles}}{volume}

                                      = \frac{3.72 \times 10^{-2}}{0.795 L}

                                      = 4.7 \times 10^{-2} mol/L

or,                                   = 0.047 M

Now, as 1 mol of IF_{7} produces 7 mol HF. So, 7 \times 3.72 \times 10^{-2} = 26.04 \times 10^{-2} M HF.

Therefore, concentration of HF will be calculated as follows.

             Concentration of HF = \frac{0.2604}{0.795}

                                              = 0.33 M

Thus, we can conclude that concentration of periodic acid is 0.047 M and concentration of hydrofluoric acid is 0.33 M.    

8 0
3 years ago
What is 31 degrees Celsius in Fahrenheit
vovangra [49]
87.8 , 31 Celsius=87.8(88) in Fahrenheit
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What factor determines whether an acid or base is strong or weak?
SOVA2 [1]

Answer:

i think it's c

Explanation:

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