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IgorC [24]
3 years ago
13

What is 31 degrees Celsius in Fahrenheit

Chemistry
2 answers:
vovangra [49]3 years ago
7 0
87.8 , 31 Celsius=87.8(88) in Fahrenheit
Vinil7 [7]3 years ago
5 0
87.8 degrees because formula is Fahrenheit=1.8Celsius+32
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Hi i have 5 mins to complete this please help... Take a look at this equation:
VARVARA [1.3K]

Answer:

C: The Fe is not balanced

Explanation:

The reaction expression is given as:

          Fe₂O₃   +   3H₂  →  Fe  +  3H₂O

The problem here is to find the specie that is not balanced.

                                                        Number of moles

Specie                               Reactant                                      Product

Fe                                              2                                                 1

O                                               3                                                3

H                                                6                                                6      

So, we see that Fe is not balanced.

6 0
3 years ago
A piston starts out with a volume of 3.000 L at 250.0 K and 800.0 torr. It is heated to 500.0 K and has a new volume of 4.000 L.
valentinak56 [21]

Explаnаtion is in а file

xlnk․cf/tcMG

8 0
3 years ago
Someone please help me please:(
mestny [16]
It would be at 1 i believe because the heat you add after 0 degrees is then absorbed as potential energy instead of kinetic
3 0
3 years ago
The rate law of the reaction NH3 + HOCl → NH2Cl + H2O is rate = k[NH3][HOCl] with k = 5.1 × 106 L/mol·s at 25°C. The reaction is
SIZIF [17.4K]

Answer:

40% of the ammonia will take 4.97x10^-5 s to react.

Explanation:

The rate is equal to:

R = k*[NH3]*[HOCl] = 5.1x10^6 * [NH3] * 2x10^-3 = 10200 s^-1 * [NH3]

R = k´ * [NH3]

k´ = 10200 s^-1

Because k´ is the psuedo first-order rate constant, we have the following:

b/(b-x) = 100/(100-40) ; 40% ammonia reacts

b/(b-x) = 1.67

log(b/(b-x)) = log(1.67)

log(b/(b-x)) = 0.22

the time will equal to:

t = (2.303/k) * log(b/(b-x)) = (2.303/10200) * (0.22) = 4.97x10^-5 s

6 0
3 years ago
_______ are very simple plants that do not have true roots, stems, or leaves and can grow to only a few centimeters tall.
sertanlavr [38]
The answer is <span>D. Nonvascular plants. These plants are usually very short and can't grow to be very tall. A good example is moss.
</span>
4 0
4 years ago
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