Answer: 1. The total ion concentrations of both solution A and B are equal. Therefore, there is no net flow of water molecules.
2. The total ion concentrations of the solutions A is greater than that of solution B. Therefore, there is a net flow of water molecules towards A.
3. The total ion concentrations of the solutions B is greater than that of solution A. Therefore, there is a net flow of water molecules towards B.
<em>Note: The question did not provide any reference solutions and their concentrations. Assuming the following pairs of solution and their given concentrations:</em><em> </em>
1. Solution A: 0.10M NaCl(aq) Solution B: 0.10M KBr (aq)
2. Solution A: 0.20M Al(NO3)3 solution B: 0.10M NaNO3
3. Solution A: 0.10M CaCl2 Solution B: 0.50M KCl
Explanation:
An electrolyte is a chemical substance that is decomposed when an electric current is passed through it either in its molten or solution form.
When there is 100% dissociation of electrolytes, the individual ions in the substance are free to move. Therefore, it is necessary to consider the concentration of ions instead of solution concentration. The movement of water across the semipermeable membrane depends on the concentration of ions in each solution.This net movement of water molecules through a semipermeable membrane is from a low concentrated solution to the higher concentrated solution and is known as osmosis
.
First, calculate the concentrations of each solution A and B and indicate the movement of water molecules from low to high concentrated solutions as follows.
It is given that the electrolytes dissociate 100%(completely) into ions;
1) Solution A: 0.10M NaCl(aq) Solution B: 0.10M KBr (aq)
Calculate the concentration of ions in solutions A and B using,
Total ion concentration = M
o
l
a
r
i
t
y × N
umber o
f ions
Solution A: Total ion concentration = 0.10 × 2 = 0.20M
Solution B: Total ion concentration = 0.10 × 2 = 0.20M
<em>The total ion concentrations of both solution A and B are equal. Therefore, there is no net flow of water molecules.
</em>
2) Solution A: 0.20M Al(NO3)3 solution B: 0.10M NaNO3
Calculate the concentration of ions in solutions as follows
;
Total ion concentration = M
o
l
a
r
i
t
y × N
umber o
f i
ons
Solution A: Total ion concentration = 0.20 × 4 = 0.80M
Solution B: Total ion concentration = 0.10 × 2 = 0.20M
<em>The total ion concentrations of the solutions A is greater than that of solution B. Therefore, there is a net flow of water molecules towards A.
</em>
3) Solution A: 0.10M CaCl2 Solution B: 0.50M KCl
Calculate the concentration of ions in solutions A and B using,
Total ion concentration = M
o
l
a
r
i
t
y × N
umber o
f i
ons
Solution A: Total ion concentration = 0.10 × 3 = 0.30M
Solution B:
0.50 × 2 = 1.0M
<em>The total ion concentrations of the solutions B is greater than that of solution A. Therefore, there is a net flow of water molecules towards B.
</em>
