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kirill [66]
3 years ago
12

Which main intermolecular force must be overcome to sublime solid NH3?

Chemistry
1 answer:
lys-0071 [83]3 years ago
6 0

Sublimation is the phase transition of a substance directly from the solid to the gaseous phase without passing through the liquid phase.

Here are the three forces that exist between two NH3 molecules:

1- Dispersion forces - these forces exist between ANY two molecules, regardless of anything else.

2- Dipole-dipole interactions - NH3 is a polar molecule with a permanent separation of charge. Each molecule behaves  like a tiny magnet and has + and - poles so 2 NH3 molecules attract each other. Dipole-dipole interactions are stronger than dispersion forces in small molecules.  

3- Hydrogen bonding - H is directly bonded to the extremely electro negative atoms N, O, or F, hence hydrogen atom is nearly stripped off electrons due to the large electro - negativity difference. Hydrogen being a small atom further reduces in size even allowing it to approach other molecules very closely. Here N,O,F gathers more partial negative charge.

Due to the close approach between the molecules and the strong partial charges, hydrogen bonding is generally more important than dipole-dipole interactions.

So the main intermolecular force must be hydrogen bonding.

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Which term describes a chemical equation in which all highly soluble compounds are written as dissociated ions
BartSMP [9]

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4 0
3 years ago
Calculate the mass of magnesium oxide produced when 0.645 g of magnesium hydroxide is the is completely decomposed.
FrozenT [24]

Answer:

0.44g

Explanation:

Given parameters:

Mass of magnesium hydroxide = 0.645g

Solution

The balanced reaction equation is shown below:

                             Mg(OH)₂ → MgO + H₂O

From the equation above, we see that the number of atoms are conserved.

To find the mass of magnesium oxide produced, we find the number moles of the decomposed magnesium hydroxide first:

      Molar mass of Mg(OH)₂ = 24 + 2(16+1) = 58g/mol

Number of moles of Mg(OH)₂ = \frac{mass}{molar mass}

                                                  =  \frac{0.645}{58}

                                                  = 0.011mole

Now, from the balanced equaiton, we know that:

     1 mole of Mg(OH)₂ produces 1 mole of MgO

Therefore, 0.011mole of Mg(OH)₂ will produce 0.011mole of MgO

so mass of MgO = number of moles of MgO x molar mass of MgO

   Molar mass of MgO = 24 + 16 = 40g/mol

     mass of MgO = 0.011 x 40 = 0.44g

8 0
3 years ago
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