Answer:
-66.88KJ/mol
Explanation:
It is possible to obtain the heat involved in a reaction using a calorimeter. Formula is:
q = -C×m×ΔT
<em>Where q is heat of reaction, C is specific heat capacity (4.18J/°Cg), m is mass of solution (100.0g) and ΔT is temperature change (23.40°C-22.60°C = 0.80°C)</em>
Replacing:
q = -4.18J/°Cg×100.0g×0.80°C
q = -334.4J
Now, in the reaction:
Ag⁺ + Cl⁻→ AgCl
<em>AgNO₃ as source of Ag⁺ and HCl as source of Cl⁻</em>
Moles that react are:
0.050L× (0.100mol /L) = 0.0050moles
If 0.0050 moles produce -334.4J. Heat of reaction is:
-334.4J / 0.0050moles = -66880J/mol = <em>-66.88KJ/mol</em>
Answer: the density is 997 kg
Explanation:
Answer:
2Fe + 6HC2H3O2 → 2Fe(C2H3O2)3 + 3H2
Explanation:
There you go
Answer:
B. CaCl + LiCO3 yields CaCO3 + LiCl is not correct
It should be CaCl2 + Li2CO3 → 2LiCl + CaCO3
Explanation:
For a reaction to be double displacement reaction there are two things we need to look for
1) There must be an interchange of the group of ions
2) The reactants must dissolve in water to release ions
A. 2RbNO3 + BeF2 yields Be(NO3)2 + 2RbF
2Rb+ + NO3- + Be^2+ + 2F- → Be(NO₃)₂ + 2RbF
This is correct
B. CaCl + LiCO3 yields CaCO3 + LiCl
This is not correct
The correct equation is:
CaCl2 + Li2CO3 → Ca2+ + 2Cl- + 2Li+ + CO3^2- → 2LiCl + CaCO3
C. Na3PO4 + 3KOH yields 3NaOH + K3PO4
3Na+ + PO4^3- + 3K+ + 3OH- → 3NaOH + K3PO4
This is correct
D. 2MgI2 + Mn(SO3)2 yields 2MgSO3 + MnI4
2Mg^2+ + 4I- + Mn^4+ + 2SO3^2- → 2 MgSO3 + MnI4
This is correct
