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Alisiya [41]
3 years ago
8

What is the total mass of 2.0 moles of h2( g.??

Chemistry
1 answer:
irinina [24]3 years ago
6 0
When we speak of hydrogen, the assumption is that it is hydrogen gas, H2, and not atomic hydrogen. Since hydrogen is diatomic, 1 mol of H2 has a mass of 2.0 grams. Therefore, 2 moles will have a mass of 4.0 grams.

Likewise, 0.5 grams is 1/4 of the mass of 1 mole (2.0 g), so the answer is 0.25 mol H2.

You can even set up a conversion factor to get the answer.
0.5 g H2 x (1 mol H2 / 2.0 g H2) = 0.25 mol H2
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1/2-life of pyruvic acid in the presence of aminotransferase enzyme (which converts it to alanine) was found to be 221 s. how lo
Ugo [173]

Answer:

After 1326s, the concentration of pyruvic acid fall to 1/64 of its initial concentration.

Explanation:

The first order kinetics reaction is:

ln [A] = ln [A]₀ - kt

<em>Where [A] is concentration after t time, [A]₀ is intial concentration and k is reaction constant.</em>

To convert half-life to k you must use:

t(1/2) = ln 2 / K

221s = ln 2 / K

K = ln 2 / 221s

<h3>K = 3.1364x10⁻³s⁻¹</h3>

If [A] = 1/64, [A]₀ = 1:

ln [A] = ln [A]₀ - kt

ln (1/64) = ln 1 - 3.1364x10⁻³t

4.1588 = 3.1364x10⁻³s⁻¹t

1326s = t

<h3>After 1326s, the concentration of pyruvic acid fall to 1/64 of its initial concentration.</h3>

<em />

6 0
3 years ago
The ability of a substance to combine chemically with another substance.
Marysya12 [62]
Reactivity. It is the ability of matter to combine chemically with other substances.
8 0
2 years ago
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Answer:

The answer you selected is correct (A)have

Explanation:

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5 0
2 years ago
Potassium iodide reacts with lead(II) nitrate in this precipitation reaction: 2 KI(aq) + Pb(NO3)2(aq) → 2 KNO3(aq) + PbI2(s) Wha
andrew11 [14]

Answer:

a. 174 mL

Explanation:

Let's consider the following reaction.

2 KI(aq) + Pb(NO₃)₂(aq) → 2 KNO₃(aq) + PbI₂(s)

We have 155.0 mL of a 0.112 M lead(II) nitrate solution. The moles of Pb(NO₃)₂ are:

0.1550 L × 0.112 mol/L = 0.0174 mol

The molar ratio of KI to Pb(NO₃)₂ is 2:1. The moles of KI are:

2 × 0.0174 mol = 0.0348 mol

The volume of a 0.200 M KI solution that contains 0.0348 moles is:

0.0348 mol × (1 L / 0.200 mol) = 0.174 L = 174 mL

5 0
2 years ago
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