Question

How do I solve this?

Answer 1

Answer:

The heat contained is 1236 Joules

Explanation:

As we know

$Q = mc\Delta$T

Where

$\Delta$T is the change in temperature

m is the mass in grams

c is the specific heat of water (ice) = 2.06 joules/gram

Substituting the given values, we get -

$Q = 20 * (-15+45)*2.06\\Q = 20*2.06*30\\Q = 1236$Joules