So we have to find b we are going to try to isosiate b
4b - 3 > -1 now we are going to isosiate the b so add 3 from both side and get 4b > 2
Answer:
$0.90
Step-by-step explanation:
A 10-minute call exceeds the 3-minute initial period by 7 minutes. The initial period charge is 37¢. The additional minute charge is 7·9¢ = 63¢. Then the regular charge for that call is ...
37¢ +63¢ = 100¢ = $1.00
The 10% discount reduces the charge by ...
10% × $1.00 = $0.10
so the final cost of the 10-minute call is ...
$1.00 -0.10 = $0.90 . . . . . cost of the call
700 is what is half of that I think
Answer:
C
Step-by-step explanation:
The graph has a x - axis of amount of scarves in intervals of 1 and a y - axis of hours in intervals of 20
Using this information we can see that in the ordered pair, 1 represents x and 16 represents y, which means that the scarves ar 1 and the hours are 16 in the ordered pair
C makes the most logical sense because there is nothing about centimeters in the graph and the scarves are not in the y, but rather in the x
Vote Brainliest, Thx:)
Answer:
See explanation and hopefully it answers your question.
Basically because the expression has a hole at x=3.
Step-by-step explanation:
Let h(x)=( x^2-k ) / ( hx-15 )
This function, h, has a hole in the curve at hx-15=0 if it also makes the numerator 0 for the same x value.
Solving for x in that equation:
Adding 15 on both sides:
hx=15
Dividing both sides by h:
x=15/h
For it be a hole, you also must have the numerator is zero at x=15/h.
x^2-k=0 at x=15/h gives:
(15/h)^2-k=0
225/h^2-k=0
k=225/h^2
So if we wanted to evaluate the following limit:
Lim x->15/h ( x^2-k ) / ( hx-15 )
Or
Lim x->15/h ( x^2-(225/h^2) ) / ( hx-15 ) you couldn't use direct substitution because of the hole at x=15/h.
We were ask to evaluate
Lim x->3 ( x^2-k ) / ( hx-15 )
Comparing the two limits h=5 and k=225/h^2=225/25=9.
