For an individual die roll, the probability of rolling 6 is \dfrac{1}{6}
6
1
.
Effectively, this problem is asking for P(\text{1st roll is 6}\cap\text{2nd roll is 6})P(1st roll is 6∩2nd roll is 6).
Using the rule of product, this is:
\dfrac{1}{6}\times\dfrac{1}{6}=\dfrac{1}{36}
6
1
×
6
1
=
36
1
.
Step-by-step explanation:
the opposite angles are always same.
|RZ|=0.5|SW| therefore 2|RZ|=|SW|.
5x - 20 = 2 · 30
5x - 20 = 60 |add 20 to both sides
5x = 80 |divide both sides by 5
x = 16
..............................[a+b]2+c2
So we have an equation:
2w=12-4w
Firstly, let's simplify, and divide all terms by 2:
w=6-2w
Now, we add 2w over to the other side:
3w=6
And finally, we divide both sides by 3:
w=2
Hope this helps!
