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Sergeu [11.5K]
3 years ago
13

Please help asapp 25 pts

Mathematics
2 answers:
leonid [27]3 years ago
8 0
\dfrac{x^2-2x-24}{x^2-5x-36}=\dfrac{x^2-6x+4x-24}{x^2-9x+4x-36}\\\\=\dfrac{x(x-6)+4(x-6)}{x(x-9)+4(x-9)}=\dfrac{(x-6)(x+4)}{(x-9)(x+4)}\\\\=\boxed{Answer:\ \dfrac{x-6}{x-9}}
Ad libitum [116K]3 years ago
3 0
\frac{x^{2}-2x-24}{x^{2}-5x-36} =  \frac{(x-6)(x+4)}{(x-9)(x+4)} = \frac{x-6}{x-9} 

Answer is A.
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3 0
3 years ago
the current value of a new car is 18,000. the car will depreciate 15% per year over the next 5 year. which exponential equation
Arte-miy333 [17]

The exponential equation that models this situation is:

V(t) = 18000(0.85)^t, 0 \leq t \leq 5.

<h3>What is an exponential function?</h3>

A decaying exponential function is modeled by:

A(t) = A(0)(1 - r)^t

In which:

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For this problem, the parameters are:

A(0) = 18000, r = 0.15.

Hence the equation for the value of the car over the next 5 years is:

A(t) = A(0)(1 - r)^t

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More can be learned about exponential functions at brainly.com/question/25537936

#SPJ1

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