We know that
speed=distance/time
distance=speed*time
in this problem
speed1=14 miles/hour
speed2=20 miles/hour
average speed=[14+20]/2-----> 17 miles/hour
time=3 2/5 hour-----> (3*5+2)/5----> 17/5 hours
distance=17*(17/5)----> 57.8 miles
the answer is
57.8 miles
Given the equation 4(3b + 2)² = 64,
dividing both sides of the equation by 4, we have
(3b + 2)² = 16 and getting the square root of both sides,
(3b + 2) = 4 and (3b + 2) = -4
We can solve for b for each equation and have
3b = 2 | 3b = -6
b = 2/3 | b = -2
Therefore, the values of b are 2/3 and -2 and from the choices, the answer is <span>A: b = 2/3 and b = -2.</span>
Answer:
Largest Median: Same
Largest Range: Castro
Largest IQR: Castro
Step-by-step explanation:
With a box-and-whisker plot, the box represents the upper and lower quartiles, the vertical line inside the box represents the median, and the lines on either side of the box show the high and low of the range.
Largest Median: Medians are the same because the verticle line inside the boxes is at 7 for both
Largest Range: Ms Castro's Class- the lines on either side of the box for Ms Castro go from 1-10 while the other class only goes from 4-10.
Largest IQR (interquartile range) Ms. Castro's class: their IQR goes from 5-8 while the other class only goes from 6-8
en la primera
es -2x+7=13, suma 13 con 7 para q tengas 20 y el negativo dos x es la otra asi agarras -2=20 ahora dividelo los dos por 2 te sale 0 para el negativo dos y divide 20/2 son X=10
