T=(60cos78, 60sin78)
T=(12.47, 58.69)
C=45
d=√((45-12.47)^2+58.69^2)
d≈67.1km
Answer:
B
Step-by-step explanation:
Data set D does not contain the value 128, which is the median value.
Data set C does not contain the outlier value 91.
Data set A contains value 168, which does not show up on the plot.
The only remaining choice is B.
_____
In order, the data values of set B are ...
... 91, 114, 120, 126, 128, 128 134, 136, 139, 142, 152
The median value of these 11 is the 6th one: 128. The median values of the remaining two sets of 5 are 120 and 139, making these values the quartiles at the ends of the box. The value 91 is more than 1.5 times the IQR (19) below the 1st quartile, so is considered an outlier. (The cutoff is 120-1.5·19=91.5.)
I think there's an image needed to answer this question?
I tried answering without, but you do need the image.
If the length is 40 and the width is 25, the ration of length:width is 40:25.
This can be simplified to 8:5
So the answer would be any drawing with the following dimensions:
1. length 8 ft and width 5 ft
2. length 16 ft and width 10 ft
3. length 24 ft and width 15 ft
4. length 32 ft and width 20 ft
5. length 40 ft and width 25 ft
It's most likely not the last 3 because the sizes are very big, but yeah a scale drawing maintains the same ratio so I assume one of the options for your answers is gonna be one of the answers from 1 - 4 above (5 is the given dimensions so I highly doubt that's the answer)