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Zina [86]
3 years ago
14

If ABCD is dilated by a factor of 2 the coordinate of b would be? Will mark barinlyist.

Mathematics
1 answer:
ch4aika [34]3 years ago
8 0

Answer:

B'(- 2, 2 )

Step-by-step explanation:

Assuming the dilatation is centred at the origin, then multiply the coordinates of B by the scale factor 2, that is

B(- 1, 1 ) → B'(2(- 1), 2(1) ) → B'(- 2, 2 )

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Find the Value of X in simplest radical form and Find the measure of angle A.​
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Answer:

A = 30°

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Step-by-step explanation:

Part A

In the drawing, we are given;

The radius of the circle with center at point S = SA = 18

ΔAHA is a right triangle

One of the leg length of ΔASH = 9

The length of the hypotenuse side of ΔASH, AS = 18 The radius of the circle with center at the point 'S'

By Pythagoras's theorem, the length of the (radius) side, AS  = √(SH² + AH²)

∴ AH = √(AS² - SH²)

AH = √(18² - 9²) = √(243) = 9·√3

AH = 9·√3

By circle theorem, SH bisects the line AH extended to the circumference of the circle

SH bisects the line with length AH + x

∴ AH = x

x = AH = 9·√3

x = 9·√3

Part B

By trigonometric ratios, we have;

sin\angle A = \dfrac{Opposite \ leg \ length}{Hypotenuse \ length}

\therefore sin\angle A = \dfrac{9}{18} = \dfrac{1}{2}

∠A = arcsine (1/2) = 30°

Angle A = 30°

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