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son4ous [18]
3 years ago
10

How do I: Express 12a as the difference of two terms

Mathematics
1 answer:
Alexeev081 [22]3 years ago
7 0

Step-by-step explanation:

12a = 13a - a

12a = 14a - 2a

12a = 15a - 3a

12a = 16a - 4a

12a = 17a - 5a

...

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530 divided by 16 give the quotient and remainder
damaskus [11]
   
 
 
          33
      _____
16 | 530
       48
      -------
         50
         48
    ----------
            2

quotient = 33
remainder = 2








6 0
3 years ago
8w – 16-20 + 7w - 11y - 4y<br> Can someone show me how to do this step by step?
AveGali [126]

Answer:

-44

Step-by-step explanation:

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Lisa's store collects 5% sales tax on every item sold. If she collected $22.00 in sales tax, what was the cost of the items her
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I did the math and i got 440
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Solve.<br> 3x + 12 = 48<br> 
Sergeu [11.5K]

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x=12

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7 0
2 years ago
Consider the differential equation <img src="https://tex.z-dn.net/?f=%20x%5E%7B2%7D%20%20%5Cfrac%7Bdy%7D%7Bdx%7D%20%3D6%20y%5E%7
Nutka1998 [239]
As a Bernoulli equation:

x^2\dfrac{\mathrm dy}{\mathrm dx}=6y^2+6xy\iff x^2y^{-2}\dfrac{\mathrm dy}{\mathrm dx}-6xy^{-1}=6

Let z=y^{-1}\implies\dfrac{\mathrm dz}{\mathrm dx}=-y^{-2}\dfrac{\mathrm dy}{\mathrm dx}. The ODE becomes

-x^2\dfrac{\mathrm dz}{\mathrm dx}-6xz=6
x^6\dfrac{\mathrm dz}{\mathrm dx}+6x^5z=-6x^4
\dfrac{\mathrm d}{\mathrm dx}[x^6z]=-6x^4
x^6z=-6\displaystyle\int x^4\,\mathrm dx
x^6z=-\dfrac65x^5+C
z=-\dfrac6{5x}+\dfrac C{x^6}
y^{-1}=-\dfrac6{5x}+\dfrac C{x^6}
y=\dfrac1{\frac C{x^6}-\frac6{5x}}
y=\dfrac{5x^6}{C-6x^5}

With y(3)=6, we get

6=\dfrac{5(3)^6}{C-6(3)^5}\implies C=\dfrac{4131}2

so the solution is

y=\dfrac{5x^6}{\frac{4131}2-6x^5}=\dfrac{10x^6}{4131-12x^5}

which is valid as long as the denominator is not zero, which is the case for all x\neq\sqrt[5]{\dfrac{4131}{12}}.
8 0
3 years ago
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