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2 years ago

Multiply & simplify (3x + 4) (x+1)

Mathematics

1 answer:

damaskus [11]2 years ago

3 0

3x^2+7x+4

Use the FOIL method, 3x•x +3x•1+4•x+4•1
3x^2+7x+4

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Which triangles are similar?

lara31 [8.8K]

I’m pretty sure it would be a and b

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2 years ago

Determine the equations of the vertical and horizontal asymptotes, if any, for y=x^3/(x-2)^4

djverab [1.8K]

Answer:

Option a)

Step-by-step explanation:

To get the vertical asymptotes of the function f(x) you must find the limit when x tends k of f(x). If this limit tends to infinity then x = k is a vertical asymptote of the function.

$\lim_{x\to\\2}\frac{x^3}{(x-2)^4} \\\\\\lim_{x\to\\2}\frac{2^3}{(2-2)^4}\\\\\lim_{x\to\\2}\frac{2^3}{(0)^4} = \infty$

Then. x = 2 it's a vertical asintota.

To obtain the horizontal asymptote of the function take the following limit:

$\lim_{x \to \infty}\frac{x^3}{(x-2)^4}$

if $\lim_{x \to \infty}\frac{x^3}{(x-2)^4} = b$ then y = b is horizontal asymptote

Then:

$\lim_{x \to \infty}\frac{x^3}{(x-2)^4} \\\\\\lim_{x \to \infty}\frac{1}{(\infty)} = 0$

Therefore y = 0 is a horizontal asymptote of f(x).

Then the correct answer is the option a) x = 2, y = 0

3 0

3 years ago

Read 2 more answers

Find the number c that satisfies the conclusion of the Mean Value Theorem on the given interval. (Enter your answers as a comma-

Shtirlitz [24]

Answer:

The number c is 2.

Step-by-step explanation:

Mean Value Theorem:

If f is a continuous function in a bounded interval [0,4], there is at least one value of c in (a,b) for which:

$f(c) = \frac{1}{b-a}\int\limits^a_b {f(x)} \, dx$

In this problem, we have that:

$f(x) = x, a = 0, b = 4$

So $f(c) = c$

----------

$f(c) = \frac{1}{b-a}\int\limits^a_b {f(x)} \, dx$

$c = \frac{1}{4-0}\int\limits^0_4 {x} \, dx$

$c = \frac{1}{4-0}*8$

$c = 2$

The number c is 2.

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2 years ago

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Answer:

Step-by-step explanation:

21 hits / 45 at bats

7/15

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2 years ago

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Step-by-step explanation:

If Candice can paint a room in 6 and Grace can paint one in 8 subtract and 6 and get 2 hours

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