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In-s [12.5K]
3 years ago
9

Solve for x: (6):-6-4 1) 36 2) 49 3) -36 0 4) -49

Mathematics
1 answer:
labwork [276]3 years ago
6 0

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Please help me answer this <br><br> Explain you’re answer <br><br> Will give braisnlt
lions [1.4K]
B the answer is B - hope this helps you out
7 0
3 years ago
Read 2 more answers
Product of 3.24<br><br> 0.45 x 0.72 <br><br> 0.45 x 72<br><br> 4.5 x 0.7<br><br> 4.5 x 7.2
natta225 [31]

Answer:

4.5 x 0.72

Step-by-step explanation:

I AM ASSUMING THAT YOU FORGOT TO ADD 2 AFTER 0.7 IN 4.5 x 0.7

4 0
3 years ago
Read 2 more answers
Two friends Ana and Juan are buying books by joining the History Book
Travka [436]

Answer:

Ana  spent $17  per book on average.

Juan  spent $14.78  per book on average.

y = $15 + 17x--------- equation 1

y= $10 + 14.78 x------------- equation 2

Step-by-step explanation:

Ana has to pay a yearly fee of $15 to join.

She spends a total of $525 for 30 books.

The amount spent on books = Total amount - yearly fee

                                                 = $525- $15= $510

Price per book on the average = $510/30= $ 17

Ana  spent $17  per book on average.

Juan has to pay a yearly fee of $10 to join.

He spends a total of $350 for 23 books.

The amount spent on books = Total amount - yearly fee

                                                 = $350- $10= $340

Price per book on the average = $340/23= $ 14.78≅ $15

Juan  spent $14.78  per book on average.

The function can be established if y gives the total cost and x gives the number of books

y = $15 + 17x--------- equation 1

y= $10 + 14.78 x------------- equation 2

Juan has a better deal because the yearly fee is less also the price per book is less.

8 0
3 years ago
A 3-pound bag of bananas costs $2.88. What is the price per ounce?
Alborosie

Answer: 6 cents

Step-by-step explanation:

1 pound = 16 ounces

3 pounds = 48 ounces

2.88 ÷ 48 = 0.06

0.06 = 6 cents.

One ounce of bananas cost 6 cents.

Hope this helps!

4 0
3 years ago
University dean is interested in determining the proportion of students who receive some sort offinancial aid. rather than exami
vladimir2022 [97]
The confidence interval is
0.59\pm0.081

We first find p, our sample proportion.  118/200 = 0.59.

Next we find the z-score associated with this level of confidence:
Convert 98% to a decimal: 98% = 98/100 = 0.98
Subtract from 1:  1-0.98 = 0.02
Divide by 2:  0.02/2 = 0.01
Subtract from 1:  1-0.01 = 0.99

Using a z-table (http://www.z-table.com) we see that this value is associated with a z-score of 2.33.

The margin of error (ME) is given by
ME=z\sqrt{\frac{p(1-p)}{n}}&#10;\\&#10;\\=2.33\sqrt{\frac{0.59(1-0.59)}{200}}=2.33\sqrt{\frac{0.2419}{200}}\approx0.081

This gives us the confidence interval 
0.59\pm0.081
8 0
4 years ago
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