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3 years ago

Solve for x in 2 - 3(x + 4) = 8

Mathematics

2 answers:

AysviL [449]3 years ago

7 0

Answer:

x = -6

Step-by-step explanation:

2 - 3(x + 4) = 8

=> 3(x + 4) = 2 - 8 = -6

=> x + 4 = -6/3 = -2

=> x = -2 - 4 = -6

neonofarm [45]3 years ago

6 0

x = 2

Step-by-step explanation:

2 - 3x - 12 = 8

=> 3x - 12 = 2 - 8

=> 3x - 12 = -6

=> 3x = 6

=> x = 2

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Resultant Terms in Exponential Form 13^-11 * 13^16 * 13^-3 * 13^4 * 13^-5

Yuki888 [10]

Easy
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6 0

3 years ago

What is the average value of latex: y=\tan\left(\frac{x^2}{9}\right) y = tan ⁡ ( x 2 9 ) on the closed interval [1.25, 2]?

german

For this case we have the following function:
$f(x) = tan(\frac{x^2}{9})$
The average rate of change is given by:
$AVR = \frac{f(x2) - f(x1)}{x2- x1}$
Evaluating the function for the given interval we have:
For x = 1.25:
$f(1.25) = tan(\frac{1.25^2}{9})$
$f(1.25) = 0.18$
For x = 2:
$f(2) = tan(\frac{2^2}{9})$
$f(2) = 0.48$
Then, replacing values we have:
$AVR = \frac{0.48 - 0.18}{2 - 1.25}$
$AVR = 0.4$
Answer:
the average value of on the closed interval [1.25, 2] is:
$AVR = 0.4$

3 0

3 years ago

The box plots record data on annual

ElenaW [278]

Answer:

Honestly I can't figure it out myself, but I really want to help you.

Step-by-step explanation:

So I don't know how to write a step-by-step explanation

8 0

2 years ago

Write the point where the linear equation 3x + 4y = 12 cuts the x-axis.

Pani-rosa [81]

Answer:

When the eqn cuts the x-axis , y=0

3x=12

x=12/3

x=4

So,at x=4 is the point at which the linear equation cuts the x-axis

7 0

2 years ago

Read 2 more answers

For the function y = 3x^2 - 12x + 4, what is the mirror point for the y-intercept? Give your answer in (x,y) point form.

saveliy_v [14]

Answer:

Your in Pacyber aren't you? Mr. Breux class? Anyway the answer is (0,-4)

Step-by-step explanation:

The y intercept is (0,-4)

6 0

3 years ago