Plug 
into the equation of the ellipsoid:
Complete the square:
Then the intersection is such that
which resembles the equation of a circle, and suggests a parameterization is polar-like coordinates. Let
(Attached is a plot of the two surfaces and the intersection; red for the positive root 
, blue for the negative)
Answer:
(a) discriminant is positive, 76
(b) the above tells you there are two real roots
Step-by-step explanation:
the discriminant is 'b² - 4ac'
3x² - 2x - 6 = 0 ∴ a = 3, b = -2, c = -6
(-2)² - 4(3)(-6) = 4 + 72
Answer: h(4) = 7
Step-by-step explanation:
Given h(x)= 2x-1
Find h(4)
Solution:
Substitute x = 4 into the equation
h (4) = 2 (4) - 1
h (4) = 8 - 1
h (4) = 7
Answer:
p=4
Step-by-step explanation:
because 5 is less than or equal to four!
another number grater than five no less than
so the answer is p=4
9) x.14 = 6.26 ==> 14x=156 ==> x=11.1
12) OAB = Right Triangle : (27+24)² = 24² + AB² (Pythagoras)
==> 51² =24² + AB² ==> 2,601 = 576 + AB² ==> AB² = 2,601 - 576 = 2,025
==> AB² = 2015 AND AB =√2025 = 45
Sorry I can't read the last page
