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fiasKO [112]
3 years ago
6

If my dog has a mass of 30.0 lbm, how much does my dog weigh on top of Mt Everest? (g = 32.042 ft/s2) W = m* g • Therefore, 1 lb

m # 1 lbf
Chemistry
1 answer:
laila [671]3 years ago
6 0

Answer:

The dog weighs 29,88 lbf at the top of the Everest

Explanation:

The difference between mass and weight is that <em>mass is the amount of matter in a material</em>, while <em>weight is a measure of how the force of gravity acts upon that mass.</em>

So mass remains constant always, while weight depends on gravity. At the same time, on Earth, gravity varies slightly depending on the distance to the center of Earth. At the top of Mountain Everest, gravity has a value of 32,042 ft/s2 (normally we use 32, 174 ft/s3 as the average gravity value of Earth) so the weight of the dog will be:

W=m*g.............

W=30 lbm * 32,042 \frac{ft}{s2}= 961,26 \frac{lbmft}{s2}*\frac{1lbf}{32,174lbmft/s2} =29,88 lbf

<em>Note that normally 1 lbm </em><u><em>has a weight</em></u><em> of 1 lbf  because 1 lbf = 32,174 lbmft/s^2 (the average value of gravity in Earth)</em>

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To learn more about pipette, here:-

brainly.com/question/15343680

#SPJ4

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