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ki77a [65]
3 years ago
8

What is the mass number of Carbon–12, which has 6 protons and 6 neutrons?

Chemistry
1 answer:
vivado [14]3 years ago
7 0

12.0107u is the mass number of carbon.

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Which statement describes conditions in which a mineral can form?
Alex_Xolod [135]
The answer is A. Hope this helped
8 0
3 years ago
If a molecule has four hybrid sp3 orbitals, it can be concluded that the molecule has a
Vinil7 [7]
If a molecule has four hybrid sp3 orbitals, it can be concluded that the molecule has a TETRAHEDRAL GEOMETORY
7 0
3 years ago
For the following reaction in aqueous solution, identify all those species that will be spectator ions. Select all that apply.
uranmaximum [27]

The reaction is incorrect. The correct reaction is: Na₂SO₄ + Hg(NO₃)₂ → HgSO₄ + 2NaNO₃. The options are:

A. Hg₂SO₄

B. Na₂SO₄

C. Na⁺

D. NO₃⁻

E. SO₄⁻²

F. Hg₂(NO₃)₂

G. NaNO₃

H. Hg⁺²

Answer:

C, D, E, H

Explanation:

The ions are formed after dissociation of the compound in the solution. When they're negatively charged, they're called anions, when they're negatively charged, they're called cations. If the ion is presented on both sides of the reaction, it is called a spectator ion.

Thus, the reaction given:

Na₂SO₄ + Hg(NO₃)₂ → HgSO₄ + 2NaNO₃

So, let's do the dissociation.

Na₂SO₄ is formed by the ions Na⁺ and SO₄⁻²;

Hg(NO₃)₂ is formed by the ions Hg⁺² and NO₃⁻;

HgSO₄ is formed by the ions Hg⁺² and SO₄⁻²;

NaNO₃ is formed by the ions Na⁺ and NO₃⁻.

Thus, the spectator ions are Na⁺, SO₄⁻², Hg⁺², and NO₃⁻.

7 0
3 years ago
Calculate the Empirical Formula for the following compound:<br> 0.300 mol of S and 0.900 mole of O.
ziro4ka [17]

Answer:

\boxed {\boxed {\sf SO_3}}

Explanation:

An empirical formula shows the smallest whole-number ratio of the atoms in a compound.

So, we must calculate this ratio. Since we are given the amounts of the elements in moles, we can do this in just 2 steps.

<h3>1. Divide </h3>

The first step is division. We divide the amount of moles for both elements by the <u>smallest amount of moles</u>.

There are 0.300 moles of sulfur and 0.900 moles of oxygen. 0.300 is smaller, so we divide both amounts by 0.300

  • Sulfur: 0.300/0.300= 1
  • Oxygen: 0.900/0.300= 3

<h3>2. Write Empirical Formula</h3>

The next step is writing the formula. We use the numbers we just found as the subscripts. These numbers go after the element's symbol in the formula. Remember sulfur is S and there is 1 mole and oxygen is O and there are 3 moles.

  • S₁O₃

This formula is technically correct, but we typically remove subscripts of 1 because no subscript implies 1 representative unit.

  • SO₃

\bold {The \  empirical \ formula \ for \ the \  compound \ is  \ SO_3}}

6 0
3 years ago
Question 5 options: The cell potential for an electrochemical cell with a Zn, Zn2 half-cell and an Al, Al3 half-cell is _____ V.
Mashcka [7]

Answer:

The voltage is  E_{cell} =  0.944 \ V

Explanation:

Generally the half reaction for Zn, Zn2 half-cell is mathematically represented as

    Zn_{(s)}   ⇔   Zn^{2+}_{ (aq)} + 2e^-    (reference study academy)

and the electric potential for this is a constant value

     E_{zn } =  -0.7618 \ V

Generally the half reaction for Al, Al3 half-cell is mathematically represented as

      Al^{3+}  _{(aq)} + 3e^-  ⇔  Al_{(s)}

and the electric potential for this is constant value  

       E_{Al  } =  -1.662 \ V

Therefore the cell potential for an electrochemical cell  is mathematically represented as

          E_{cell} =  E_{zn }  -  E_{Al }

substituting values

         E_{cell} =  -0.718  - (-1.662)

        E_{cell} =  0.944 \ V

 

4 0
3 years ago
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