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Scorpion4ik [409]
3 years ago
6

An aluminum block with a temperature of 300oC is placed into 200 milliliters of water with a temperature of 20oC. Which statemen

t best describes what will be observed in this experiment?
Group of answer choices

Heat will flow from the metal to the water until both are at the temperature of the container.

Heat will flow from the metal to the water until both are 300oC.

Heat will flow from the metal to the water until both are 20oC.

Heat will flow from the metal to the water until both are at a temperature somewhere between 20oC and 300oC.
Chemistry
1 answer:
Alja [10]3 years ago
8 0

Heat will flow from the metal to the water until both are at a temperature somewhere between 20oC and 300oC.

Explanation:

The correct option is that heat will flow from the metal to the water until both are at a temperature somewhere between 200°C and 300°C.

At this point, thermal equilibrium is established in the mixture.

  • Heat flows from a body at high temperature to the one with a low temperature.
  • Heat will flow from the metal at 300°C to the water at 200°C.
  • The heat flow will stop when both the water and aluminium block attains thermal equilibrium.
  • This would logically be at a temperature between 200 to 300°C.
  • The metal will lose heat and the water will gain heat until both are at a uniform temperature.

Learn more:

Heat and temperature brainly.com/question/914750

#learnwithBrainly

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Answer:

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Explanation:

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Answer:

ΔH = 2.68kJ/mol

Explanation:

The ΔH of dissolution of a reaction is defined as the heat produced per mole of reaction. We have 3.15 moles of the solid, to find the heat produced we need to use the equation:

q = m*S*ΔT

<em>Where q is heat of reaction in J,</em>

<em>m is the mass of the solution in g,</em>

<em>S is specific heat of the solution = 4.184J/g°C</em>

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The mass of the solution is obtained from the volume and the density as follows:

150.0mL * (1.20g/mL) = 180.0g

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q = 180.0g*4.184J/g°C*11.21°C

q = 8442J

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8.44kJ/3.15 mol

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