Answer:
Sr is the more metallic element
Bi is the more metallic element
O is the more metallic element
As is the more metallic element
Explanation:
One thing should be clear; metallic character increases down the group but decreases across the period.
Hence, as we move across the period, elements become less metallic. As we move down the group elements become more metallic.
This is the basis upon which decisions were made about the metallic character of each of the elements listed above.
Answer:
Amount of excess Carbon (ii) oxide left over = 23.75 g
Explanation:
Equation of the reaction: Fe₂O₃ + 3CO ----> 2Fe + 3CO₂
Molar mass of Fe₂O₃ = 160 g/mol;
Molar mass of Carbon (ii) oxide = 28 g/mol
From the equation of reaction, 1 mole of Fe₂O₃ reacts with 3 moles of carbon (ii) oxide; i.e. 160 g of iron (iii) oxide reacts with 84 g (3 * 28 g) of carbon (ii) oxide
450 g of Fe₂O₃ will react with 450 * 84/180) g of carbon (ii) oxide = 236..25 g of carbon (ii) oxide
Therefore the excess reactant is carbon (ii) oxide.
Amount of excess Carbon (ii) oxide left over = 260 - 236.25
Amount of excess Carbon (ii) oxide left over = 23.75 g
The element aluminum forms a cation with the charge of +3. The symbol for this ion is Al³⁺, and the name is aluminum ion. The number of electrons in this ion 10.
<h3>What are ions?</h3>
Ions are formed when an atom gains or loses electrons.
Metals form positive ions by a loss of electrons whereas non-metals form negative ions by gaining electrons.
The aluminum ion is formed when aluminum loses three electrons to form Al³⁺ ion which has 10 electrons.
in conclusion, ions are formed by a gain or loss of electrons.
Learn more about ions at: brainly.com/question/490569
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Amount of Niobium-91 initially
= 300/91 =3.2967mol
2040 years = 3 ×680 = 3 half-lives
therefore, amount left = 0.4121mol
mass of Niobium-91 remaining = 0.4121 ×91 =37.5g
<u>Answer:</u> The concentration of the diluted solution is 0.4788M
<u>Explanation:</u>
To calculate the concentration of the diluted solution, we use the following equation:
where,
are the molarity and volume of HCl solution
are the molarity and volume of the diluted HCl solution.
We are given:
Putting values in above equation, we get:
Hence, the concentration of the diluted solution is 0.4788M
