Answer:
2196 fish
Step-by-step explanation:
Weight of fish that the killer whale might eat in a month (30 days) = 14,000 lb
Weight of the fish that killer whale might eat in a day = 
lb.
Average weight of the fish that killer whale eats = 3.4 oz
Since,
1 pound(lb) = 16 ounces(oz)
So,
Weight of the fish that killer whale might eat in a day in ounces(oz) = 
oz
Since, a certain fish weighs 3.4 oz, in order to find the number of fish that killer whale must eat, we must divide the total weight in ounces by 3.4 ounces.
So, the number of fish that killer whale would eat = 
fish
Thus, the killer whale needs to eat 2196 fish.
The slopes of perpendicular lines are negative reciprocals.The slope of the given line is 4.The slope of the perpendicular is -1/4.
Now we need to find the equation of a line that has slope -1/4 and passes through the point (4, 20).
We use the point-slope form of the equation of a line, where m = slope, and the point is (x1, y1).
y - y1 = m(x - x1)
y - 20 = -1/4(x - 4)
-4y + 80 = x - 4
x + 4y = 84
Answer:
The answer is 1/2
Step-by-step explanation:
First you must the least common denominator so that you can add the two fractions. The least common denominator between 3/4 and 3/8, would be 8.
To get 3/4 to the least common denominator, you have to multiply top and bottom by 2. The product of this will be 6/8.
Next you add the two fractions: 6/8 + 3/8 = 9/8
Simplify your improper fraction to get on and 1 eighths or in number form 1 1/8
After this you must subtract how much she gave away so you can use your improper fraction to make it easier and subtract five eighths from nine eighths: 9/8 - 5/8 = 4/8
So, Luna has four eighths of a glass left but first you must simplify your answer. both 4 and 8 divide by 4 to get 1/2.
So Luna's glass only has 1/2 in the cup.
Make sure you be optimistic and see it as half full, instead of the pessimistic view of half empty. Remember to stay positive and share good vibes. Hope this answer helps you.
Supplement is 180- angle
180-95 = 85
Answer:
This describes a translation.
