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Irina-Kira [14]
3 years ago
6

the base of a ten foot ladder stands six feet from a house. How many feet up the house does the ladder reach

Mathematics
1 answer:
Ludmilka [50]3 years ago
5 0
In this problem you will need to use the Pythagorean theorem (c^2=a^2+b^2).
The a and b represents the two edges, while c is the diagonal side and it is called the hypotenuse. Since you already know what the hypotenuse is and what one of the sides already are you just have to use the problem: c^2-a^2=b^2. Then if you plug the data you already have into the problem you will get 10^2-6^2=b^2. That then equals 100-36=b^2. Then you subtract and get b^2=64. Then you square root both sides and you get the answer b=8.
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A line segment has endpoints P(-1,5)and Q(5,2) find the coordinate of that trisect the segment​
musickatia [10]

Answer:

(1, 6).  The second is (-1 + 2 + 2, 1 + 1 + 1), or (3, 3)

Step-by-step explanation:

Moving from P to Q, we see that x increases by 6  and y increases by 3.

"Trisect" means "divide into three equal subintervals."

We find (1/3) of 6 (which comes out to 2) and (1/3) of 3 (which comes out to 1).  

Thus, the first junction (between 1st and 2nd trisection) is (-1 + 2, 5 + 1), or (1, 6).  The second is (-1 + 2 + 2, 1 + 1 + 1), or (3, 3)

5 0
2 years ago
-1 2/3 divided by 6 need helo asap
emmainna [20.7K]

Answer:

-5/18

Step-by-step explanation:

-1 2/3 is equal to -5/3 and if you follow the keep change flip rule, keep -5/3 change the division sign to multiply and then flip the fraction (6/1 to 1/6) and then multiply.

-5/3 * 1/6 = -5/18

8 0
2 years ago
Read 2 more answers
Find the missing exponent. Set up an equation and solve. : x^4·x^n = x^5
algol [13]
Remember
(x^m)(x^n)=x^(m+n)
and
if a^m=a^n, where a=a then n=m


(x^4)(x^n)=x^5
(x^4)(x^n)=x^(4+n)
x^(4+n)=x^5
therefor
4+n=5
minus 4
n=1
5 0
3 years ago
Read 2 more answers
Please help fast this is due pretty soon and I have to go somewhere any explanation or answer would be great
Lostsunrise [7]
Don’t click the link it’s a hack
8 0
2 years ago
Read 2 more answers
Dinesh thinks that the point (1,3) is on the line y = 4x - 2.
olga_2 [115]

To see if the point is on the line, plug in one of the point values to see if it equals out.

y = 4x - 2         I will plug in 1 for x to see if y does = 3

y = 4(1) - 2

y = 4 - 2

y = 2           so (1, 2)

Dinesh is not correct because the point on the line when x = 1 is (1, 2) not (1, 3)

8 0
2 years ago
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