2 tens, 4 ones, 3 tenths, 5 hundredths, 7 thousandths
Using the normal distribution, it is found that there is a 0.0228 = 2.28% probability that a diode selected at random would have a length less than 20.01mm.
<h3>Normal Probability Distribution</h3>
In a normal distribution with mean
and standard deviation
, the z-score of a measure X is given by:

- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
In this problem, we have that:
- The mean is of
.
- The standard deviation is of
.
The probability that a diode selected at random would have a length less than 20.01mm is the <u>p-value of Z when X = 20.01</u>, hence:



has a p-value of 0.0228.
0.0228 = 2.28% probability that a diode selected at random would have a length less than 20.01mm.
More can be learned about the normal distribution at brainly.com/question/24663213
What’s the problem also have a good day
Answer:
There are 240 lilies in the flower shop.
Step-by-step explanation:
The ratio of number of roses to number of lilies = 3:5
Let the number of roses be represented by x, and the number of lilies be represented by y.
Given that:
of x and
of y are white.
Thus;
of x = 24
= 24
x = 6 x 24
= 144
There are 144 roses in the shop.
The ratio of number of roses to number of lilies = 3:5
So that,
= 48
y = 48 x 5 = 240
The number of lilies in the shop = 240
The ratio of number of roses to number of lilies = 144:240
= 3:5
Answer:
7/12 = 1.71428571429
Step-by-step explanation: