Answer:
The quantity of rooms registered on an offered day to a specific kind of guest certainly influences the quantity of registration on that day as can be seen underneath:
Explanation: Total Rewards guest - Total Rewards guests are those guests who have joined the dependability program and win credits on the entirety of their costs which they can later recover for a free stay or sustenance, etc. These sorts of guests are not expansive in number thus they don't put much weight on the number of registrations.
Their number can be normal with no check-ins on a specific day or a few check-ins on another day. So this kind of guest ordinarily doesn't influence the number of check-ins bigly.
Answer:
4.83%
Explanation:
Given that
Income = 28
End of period value = 2.40
Original value = 29
Recall that
HPR = ((Income + (end of period value - original value)) / original value) × 100
Therefore,
HPR = 28 + (2.40 - 29)/29 × 100
= (28 + ( - 26.6) / 29) × 100
= (1.4 / 29) × 100
= 0.04827 × 100
= 4. 83%
Answer:
- <em>As explained below, given that the score of the person is among the 0.03125 fraction of the best applicants, </em><u><em>he can count on getting one of the jobs.</em></u>
<em></em>
Explanation:
The hint is to use <em>Chebyshev’s Theorem.</em>
Chebyshev’s Theorem applies to any data set, even if it is not bell-shaped.
Chebyshev’s Theorem states that at least 1−1/k² of the data lie within k standard deviations of the mean.
For this sample you have:
- mean: 60
- standard deviation: 6
- score: 84
The number of standard deviations that 84 is from the mean is:
- k = (score - mean) / standar deviation
- k = (84 - 60) / 6 = 24 / 6 = 4
Thus, the score of the person is 4 standard deviations above the mean.
How good is that?
Chebyshev’s Theorem states that at least 1−1/k² of the data lie within k standard deviations of the mean. For k = 4, that is:
- 1 - 1/4² = 1 - 1/16 = 0.9375
- That means that half of 1 - 0.9375 are above k = 4: 0.03125
- Then, 1 - 0.03125 are below k = 4: 0.96875
Since there are 70 positions and 1,000 aplicants, 70/1,000 = 0.07. The compnay should select the best 0.07 of the applicants.
Given that the score of the person is among the 0.03125 upper fraction of the applicants, this person can count of geting one of the jobs.
Answer:
Coronado's diluted earnings per share would be 4.53
Explanation:
Net interest savings = (2040000*5%)*(1-0.35)= $66,300
Weighted average common stock outstanding=194000+(2040000/1000*10)= 214,400
Coronado's diluted earnings per share=(906,000+66,300)/214,400= $4.53
Answer:
The gain (loss) related to this transaction will Bob report on his X4 return is $38,000
Explanation:
Solution
Given that
The value of land = 57,000
Less: Bob's Adjusted Basis in the land is = -$23,000
The Built in Gain allocated to BOB = $34,000
Now,
The consideration in sales = $65,000
Less: Land Value is = -57000
Both members gain to be allocated= 8000
Hence,
The Total Gain Allocated to BOB is = 34000+(8000*50%) =
34000 = 4000
= 38,000
Note: The original $34000 of built-in gain on the contributed land must be given to the contributing partner which is Bob.
The remaining $8000 of gain must be shared equally between Bob and Frank.
So, Bob will report $38000 gain ($34,000 + (50% × $8,000)) from this transaction on his returns
