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crimeas [40]
3 years ago
12

Roseanne makes 1 1/2 L of lemonade. She pours 1/4 of liter of lemonade into a thermos to take to the park. Her brother drinks 2/

5 of the remaining lemonade. How much lemonade does Rosanne'a brother drinks?
Mathematics
1 answer:
Elis [28]3 years ago
4 0

Answer:

1/2 L

Step-by-step explanation:

She makes 1 1/2 L of lemonade i.e. 3/2 L of lemonade.

She pours 1/4 of liter of lemonade into a thermos to take to the park. The amount of lemonade left is:

3/2 - 1/4 = 1 1/4 L = 5/4 L

Her brother drinks 2/5 of the remaining lemonade. The amount of lemonade that her brother drinks is:

2/5 * 5/4 = 1/2 L

Her brother drinks 1/2 L.

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Jasmine is part of a bowling league and wants to beat the team record of an average score of 240 out of 300 possible points per
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Answer:

her score in sixth game is 270

Step-by-step explanation:

The computation of the Jasmine score in her sixth game is shown below:

Let us assume her sixth game score is x

And, the first five games are 252, 227, 210, 239, 242

And, the average score is 240

So, the following formula should be used

(252 + 227 + 210 + 239 + 242 + x) ÷ 6 = 240

252 + 227 + 210 + 239 + 242 + x = 240 × 6  

252 + 227 + 210 + 239 + 242 + x = 1,440

x = 270

Hence, her score in sixth game is 270

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3 years ago
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3 years ago
I need help with this ( please help me )
Gnom [1K]

Answer:

<7=120

<8=60

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3 0
3 years ago
The table shows the average annual cost of tuition at 4-year institutions from 2003 to 2010.
nata0808 [166]

Answer: 1) The best estimate for the average cost of tuition at a 4-year institution starting in 2020 =$ 31524.31

2) The slope of regression line b=937.97 represents the rate of change of  average annual cost of tuition at 4-year institutions (y) from 2003 to 2010(x).  Here,average annual cost of tuition at 4-year institutions is dependent on school years .

Step-by-step explanation:

1) For the given situation we need to find linear regression equation Y=a+bX for the given situation.

Let x be the number of years starting with 2003 to 2010.

i.e. n=8

and y be the average annual cost of tuition at 4-year institutions from 2003 to 2010.  

With reference to table we get

\sum x=36\\\sum y=150894\\\sum x^2=204\\\sum xy=718418

By using above values find a and b for Y=a+bX, where b is the slope of regression line.

a=\frac{(\sum y)(\sum x^2)-(\sum x)(\sum xy)}{n(\sum x^2)-(\sum x)^2}=\frac{150894(204)-(36)718418}{8(204)-(36)^2}=\frac{30782376-25863048}{1632-1296}=\frac{4919328}{336}\\\\=14640.85

and

b=\frac{n(\sum xy)-(\sum x)(\sum y)}{n(\sum x^2)-(\sum x)^2}=\frac{8(718418)-(36)150894}{8(204)-(36)^2}=\frac{5747344-5432184}{1632-1296}=\frac{315160}{336}\\\\=937.97


∴ To find average cost of tuition at a 4-year institution starting in 2020.(as n becomes 18 for year 2020 if starts from 2003 ⇒X=18)

So, Y= 14640.85 + 937.97×18 = 31524.31

∴The best estimate for the average cost of tuition at a 4-year institution starting in 2020 = $31524.31


4 0
3 years ago
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