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3 years ago

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Roseanne makes 1 1/2 L of lemonade. She pours 1/4 of liter of lemonade into a thermos to take to the park. Her brother drinks 2/

5 of the remaining lemonade. How much lemonade does Rosanne'a brother drinks?

1 answer:

Elis [28]3 years ago

4 0

Answer:

1/2 L

Step-by-step explanation:

She makes 1 1/2 L of lemonade i.e. 3/2 L of lemonade.

She pours 1/4 of liter of lemonade into a thermos to take to the park. The amount of lemonade left is:

3/2 - 1/4 = 1 1/4 L = 5/4 L

Her brother drinks 2/5 of the remaining lemonade. The amount of lemonade that her brother drinks is:

2/5 * 5/4 = 1/2 L

Her brother drinks 1/2 L.

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True or false: 1-51 = -5?

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Answer:

False

Step-by-step explanation:

Absolute value gives you a positive answer

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What’s the answer to -40 = 8(g-11)

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Answer:

g = 6

Step-by-step explanation:

- 40 = 8 ( g - 11 )

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a group of 10 people ran an average of 2.7 miles in one week. if the first 4 people in the group averaged 3 miles, what did the

FromTheMoon [43]

In this question, 10 people average running distance is 2.7miles. Then the sum of their running distance would be: 10 people * 2.7 miles/people= 27 miles.

The group then divided into 2, 4 people with 3 miles average and 6 people with unknown average. Since the people are same like the 10 people group, their total running distance would be the same. The calculation would be:

total distance = group1 * average1 + group2 * average2
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3 years ago

A ball is thrown in the air from a platform that is 96 feet above ground level with an initial vertical velocity of 32 feet per

pishuonlain [190]

Answer:

y = -16 (x - 1)^2 + 112

The object lands on the ground in approximately 3.6s

Explanation:

The equation given is that of a parabola.

Now the maximum (local) point of a parabola is the vertex. Therefore, if we want to rewrite our function in the form that would be used to find the maximum height, then that form must be the vertex form of a parabola.

The vertex form of a parabola is

$y=a(t-h)^2+k$

where (h, k) is the vertex.

The only question is, what is the vertex for our function h(t)?

Remember that if we have an equation of the form

$y=ax^2+bx+c$

then the x-coordinate of the vertex is

$h=-\frac{b}{2a}$

Now in our case b = 32 and a = -16; therefore,

$h=\frac{-32}{2(16)}=1$

We've found the value of the x-coordinate of the vertex. What about the y-coordinate? To get the y-coordinate, we put x = 1 into h(t) and get

$k=-16(1)+32(1)+96=112$

Hence, the y-coordindate is k = 112.

Therefore, the vertex of the parabola is (1, 112).

With the coordinates of the vertex in hand, we now write the equation of the parabola in vertex form.

$h(t)=a(t-1)^2+112$

The only problem is that we don't know what the value of a is. How do we find a?

Note that the point (0, 96) lies on the parabola. In other words,

$h(0)=-16(0)^2+32(0)+96=96$

Therefore, the vertex form of the parabola must also contain the point (0, 96).

Putting in t = 0, h = 96 into the vertex form gives

$96=a(0-1)^2+112$ $96=a+112$

subtracting 112 from both sides gives

$a=-16$

With the value of a in hand, we can finally write the equation of the parabola on vertex form.

$\boxed{h\mleft(t\mright)=-16\left(t-1\right)^2+112.}$

Now when does the object hit the ground? In other words, for what value of t is h(t) = 0? To find out we just have to solve the following for t.

$h(t)=0.$

We could either use h(t) = -16t^2 + 32t + 96 or the h(t) = -16(t - 1)^2 + 112 for the above equation. But it turns out, the vertex form is more convenient.

Thus we solve,

$-16\left(t-1\right)^2+112=0$

Now subtracting 112 from both sides gives

$-16(t-1)^2=-112$

Dividing both sides by -16 gives

$(t-1)^2=\frac{-112}{-16}$ $(t-1)^2=7$

taking the square root of both sides gives

$t-1=\pm\sqrt{7}$

adding 1 to both sides gives

$t=\pm\sqrt{7}+1$

Hence, the two solutions we get are

$t=\sqrt{7}+1=3.6$ $t=-\sqrt{7}+1=-1.6$

Now since time cannot take a negative value, we discard the second solution and say that t = 3.6 is our valid solution.

Therefore, it takes about 3.6 seconds for the object to hit the ground.

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1 year ago

Chris tried to rewrite the expression \left( 4^{-2} \cdot 4^{-3} \right)^{3}(4

crimeas [40]

We have been given an expression $\left( 4^{-2} \cdot 4^{-3} \right)^{3}$ . We have been given steps how Chris tried to solve the given expression. We are asked to choose the correct option about Chris's work.

Let us simplify our given expression.

Using exponent property, $a^m\cdot a^n=a^{m+n}$ , we cab rewrite our given expression as:

$\left( 4^{-2+(-3)} \right)^{3}$

$\left( 4^{-5} \right)^{3}$

Now we will use exponent property $(a^m)^n=a^{m\cdot n}$ to further simplify our expression.

$\left( 4^{-5} \right)^{3}= 4^{-5\cdot 3}$

$\left( 4^{-5} \right)^{3}= 4^{-15}$

Therefore, Chris made mistake in step 2.

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3 years ago